JDK1.8_HashMap源码之resize
2019-08-09 00:00:00
jdk1
final Node<K,V>[] resize() { //创建一个Node数组用于存放table中的元素, Node<K,V>[] oldTab = table; //获取旧table的长度 int oldCap = (oldTab == null) ? 0 : oldTab.length; //获取旧的扩容阈值 int oldThr = threshold; int newCap, newThr = 0; //如果旧的table中有元素 if (oldCap > 0) { //如果旧table长度>=最大容量限制时不进行扩容,并将扩容阈值赋值为Integer.MAX_VALUE if (oldCap >= MAXIMUM_CAPACITY) { threshold = Integer.MAX_VALUE; return oldTab; } // 将新table长度赋值为旧table的2倍, // 判断旧table长度的二倍是否小于最大容量,且旧容量大于等于初始容量, // 以上判断成立则将新的扩容阀值赋值为旧的扩容阈值的二倍 else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY && oldCap >= DEFAULT_INITIAL_CAPACITY) newThr = oldThr << 1; // double threshold } else if (oldThr > 0) // initial capacity was placed in threshold newCap = oldThr; else { // zero initial threshold signifies using defaults newCap = DEFAULT_INITIAL_CAPACITY; newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY); } if (newThr == 0) { float ft = (float)newCap * loadFactor; newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ? (int)ft : Integer.MAX_VALUE); } threshold = newThr; @SuppressWarnings({"rawtypes","unchecked"}) //将旧table中的元素放到扩容后的newTable中 Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap]; table = newTab; if (oldTab != null) { for (int j = 0; j < oldCap; ++j) { Node<K,V> e; if ((e = oldTab[j]) != null) { oldTab[j] = null; //如果数组对应下标位置只有一个元素,对hashCade取余并根据结果直接放到newTable相应的位置 if (e.next == null) newTab[e.hash & (newCap - 1)] = e; //如果数组对应下标位置的元素是一个红黑树,则拆分红黑树放到newTable中 // 如果拆分后的红黑树元素小于6,则转化为链表 else if (e instanceof TreeNode) ((TreeNode<K,V>)e).split(this, newTab, j, oldCap); else { // preserve order //数组对应下标位置的元素是一个链表的情况 //根据(e.hash & oldCap)条件对链表进行拆分并放到newTable Node<K,V> loHead = null, loTail = null; Node<K,V> hiHead = null, hiTail = null; Node<K,V> next; do { next = e.next; if ((e.hash & oldCap) == 0) { if (loTail == null) loHead = e; else loTail.next = e; loTail = e; } else { if (hiTail == null) hiHead = e; else hiTail.next = e; hiTail = e; } } while ((e = next) != null); if (loTail != null) { loTail.next = null; newTab[j] = loHead; } if (hiTail != null) { hiTail.next = null; newTab[j + oldCap] = hiHead; } } } } } return newTab; }
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