go语言中实现数组随机输出打印示例代码

go随机打乱列表数组，可以通过rand.Perm()函数完成

代码示例：对列表数组进行洗牌

1.随机洗牌函数编写

\models\helpers.go

 //公共函数
 package models

 import (
	"fmt"
	"math/rand"
	"time"
 )

 //对列表数组进行随机/洗牌
 func ShuffleList(start, end int) []int {
	if end < start {
		start, end = end, start
	}

	length := end - start
	rand.Seed(time.Now().UTC().UnixNano())

	list := rand.Perm(length)
	for index, _ := range list {
		list[index] += start
	}
	return list
 }

2.控制器调用测试

package controllers

import (
	"fmt"
	"gblog/models"

)

// TestController  is a test control
type TestController struct {
	//beego.Controller
	BaseController
}

func (c *TestController) Aaa() {

	mapList := make([]map[int]int, 4)
	mapList[0] = map[int]int{1: 1}
	mapList[1] = map[int]int{2: 2}
	mapList[2] = map[int]int{3: 3}
	mapList[3] = map[int]int{4: 4}
	//随机洗牌
	shuffled := models.ShuffleList(0, len(mapList))

	fmt.Printf("map数据  :  %v\n", mapList)
	fmt.Printf("洗牌后的map数据  :  %v\n", shuffled)
}

效果：