对多个数组中的列值求和
我有一个具有动态名称的数组。我的数组可以大于3,取决于数组变量,并且数组变量应该是唯一的
$loopThrice = 3;
$getSum = 0;
$total = array();
$array0 = array(5, 10, 15, 20, 25, 30);
$array1 = array(1, 2, 3, 4, 5, 6);
$array2 = array(2, 6, 8, 10, 12, 14);
for($a=0; $a < $loopThrice; $a++){ // loop 3x to get unique array name
foreach (${'array'.$a} as $key => $value) { // $array0, $array1, $array2,
//Right here is my problem, I'm not sure if this the correct way to get the sum of $array0,1,2
//get the sum of array0,1,2 -- newarray(8, 18, 26, 34, 42, 50)
$getSum +=
//store newarray
array_push($total, $getSum);
}
}
我需要获得如下输出:
Array (
[0] => 8
[1] => 18
[2] => 26
[3] => 34
[4] => 43
[5] => 50
)
解决方案
为什么不使用多维数组?
$array = array(); // hungarian notation
$array[] = array(5, 10, 15, 20, 25, 30);
$array[] = array(1, 2, 3, 4, 5, 6);
$array[] = array(2, 6, 8, 10, 12, 14);
在本例中,您将拥有一个数组数组:
Array
(
[0] => Array
(
[0] => 5
[1] => 10
[2] => 15
[3] => 20
[4] => 25
[5] => 30
)
[1] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
)
[2] => Array
(
[0] => 2
[1] => 6
[2] => 8
[3] => 10
[4] => 12
[5] => 14
)
)
您可以使用嵌套的for
循环:
$sumArray = array();
$arrayCount = count($array);
$elementCount = 0;
foreach($array as $subarray)
{
$count = count($subarray);
$elementCount = $elementCount < $count ? $count : $elementCount;
}
for($i = 0; $i < $elementCount; $i++)
{
$sumArray[$i] = 0;
for($j = 0; $j < $arrayCount; $j++)
{
$sumArray[$i] += $array[$j][$i];
}
}
print_r($sumArray);
输出为
Array
(
[0] => 8
[1] => 18
[2] => 26
[3] => 34
[4] => 42
[5] => 50
)
现在,如果您有一个不成比例的子数组(即每个子数组中的元素计数不同),您仍然会得到某种结果,因为丢失的元素将被假定为0
。因此,输入:
$array = array(); // hungarian notation
$array[] = array(5, 10, 15, 20, 25);
$array[] = array(1, 2, 3, 4, 5, 6);
$array[] = array(2, 6, 8, 10);
您仍将获得结果:
Array
(
[0] => 8
[1] => 18
[2] => 26
[3] => 34
[4] => 30
[5] => 6
)
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