C语言详细讲解通过递归实现扫雷的展开
用户选择菜单
void menu()
{
printf("****************************\n");
printf("******** 1.play **********\n");
printf("******** 0.exit **********\n");
printf("****************************\n");
}
用户按1进入游戏
棋盘初始化
void Itnboard(char board[ROWS][COLS], int rows, int cols,char c)
{
int i, j;
for (i = 0; i < rows; i++)
{
for (j = 0; j <cols; j++)
{
board[i][j] = c;
}
}
}
创建数组,并对其进行初始化
布置雷(随机布置)
void Setboard(char board[ROWS][COLS], int row, int col)
{
int count = Easy_count;
while (count)
{
int x = rand() % row+1;
int y = rand() % col+1;
if (board[x][y] == '0')
{
board[x][y] = '1';
count--;
}
}
}
用time函数产生随机值
打印棋盘
void Displayboard(char board[ROWS][COLS], int row, int col)
{
int i, j;
for (i = 0; i <= col; i++)
{
printf("%d ", i);
}
printf("\n");
for (i = 1; i <= row; i++)
{
printf("%d ", i);
for (j = 1; j <= col; j++)
{
printf("%c ", board[i][j]);
}
printf("\n");
}
}
打印棋盘
玩家下棋
void Player(char board[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
int x, y;
int count = 0;
while (1)
{
printf("请排雷:\n");
scanf("%d %d", &x, &y);
if (x >= 1 && x <= 9 && y >= 1 && y <= 9)
{
if (board[x][y] == '0')
{
Openboard(show, board, x, y);
Displayboard(show, ROW, COL);
}
else if (board[x][y] == '1')
{
printf("你死了\n");
break;
}
}
else
{
printf("请重新输入");
}
int i, j;
for (i = 1; i <= row; i++)
{
for (j = 1; j <= col; j++)
{
if (show[i][j] == '*')
{
count++;
}
}
}
if (count == Easy_count)
{
printf("成功\n"); //这里的判断条件是遍历整个数组,统计雷的个数,如果雷的个数等于所剩余未排的*,说明排雷成功
break;
}
}
}
用户输入值,并进行判断,如果该位置没有雷,我们进入展开函数
棋盘展开
void Openboard(char show[ROWS][COLS], char board[ROWS][COLS], int row, int col)
{
if (row >= 1 && row <= ROW && col >= 1 && col <= COL)
{
int count=sum(board, row, col);
if (count != 0)
{
show[row][col] = count + '0';
}
else if (show[row][col] != '_')
{
show[row][col] = '_';
int i = 0, j = 0;
for (i = row - 1; i <= row + 1; i++)
{
for (j = col - 1; j <= col + 1; j++)
{
Openboard(show, board, i,j);
}
}
}
else
{
return;
}
}
}
如果用户输入的这个位置没有雷,我们对其周围8个位置进行判断是否有雷,若有雷,我们把雷的个数显示在该位置上,若其周围8个位置没有雷并且不是下划线,我们把这个位置赋值为下划线,然后并对其8个位置进行同样的判断,如果周围没雷,而且周围的棋子也不是下划线,我们对其进行返回。
展开部分思维导图
展开函数最后一个else return 作用
这里我们show棋盘有三种情况,
1.该位置是*
2.该位置是下划线
3.该位置是雷的个数
else
return;
这里是作用:如果是下划线,我们就返回上一层函数。因为如果这里不是下划线,我们会在else return 之前的语句中进行判断,并对其周围8个位置进行操作,然后再对这8个棋子各个周围8个位置进行判断并操作,如果这里是下划线,就说明由这个位置为中心的周围8个棋子已经判断过了,并且以这8个位置为中心,已经递归过了,我们不需要再进行判断,所以直接返回就行
周围雷个数判断
int sum(char board[ROWS][COLS], int x, int y)
{
return (board[x - 1][y - 1] +
board[x - 1][y] +
board[x - 1][y + 1] +
board[x][y - 1] +
board[x][y + 1] +
board[x + 1][y - 1] +
board[x + 1][y] +
board[x + 1][y + 1] - 8 * '0');
}
test.c
#include"game.h"
void menu()
{
printf("****************************\n");
printf("******** 1.play **********\n");
printf("******** 0.exit **********\n");
printf("****************************\n");
}
void game()
{
char board[ROWS][COLS] = { 0 };
char show[ROWS][COLS] = { 0 };
Itnboard(board, ROWS, COLS,'0'); //初始化棋盘
Itnboard(show, ROWS, COLS, '*');
Setboard(board, ROW, COL);
Displayboard(board, ROW, COL);
Player(board, show, ROW, COL); //玩家输入
}
int main()
{
int input=1;
srand((unsigned int)time(NULL));
do{
menu();
scanf("%d", &input);
switch (input)
{
case 1:
game();
break;
case 0:
break;
default:
printf("输入错误请重新输入:\n ");
}
} while (input);
}
game.c
#include"game.h"
void Itnboard(char board[ROWS][COLS], int rows, int cols,char c)
{
int i, j;
for (i = 0; i < rows; i++)
{
for (j = 0; j <cols; j++)
{
board[i][j] = c;
}
}
}
void Displayboard(char board[ROWS][COLS], int row, int col)
{
int i, j;
for (i = 0; i <= col; i++)
{
printf("%d ", i);
}
printf("\n");
for (i = 1; i <= row; i++)
{
printf("%d ", i);
for (j = 1; j <= col; j++)
{
printf("%c ", board[i][j]);
}
printf("\n");
}
}
void Setboard(char board[ROWS][COLS], int row, int col)
{
int count = Easy_count;
while (count)
{
int x = rand() % row+1;
int y = rand() % col+1;
if (board[x][y] == '0')
{
board[x][y] = '1';
count--;
}
}
}
int sum(char board[ROWS][COLS], int x, int y)
{
return (board[x - 1][y - 1] +
board[x - 1][y] +
board[x - 1][y + 1] +
board[x][y - 1] +
board[x][y + 1] +
board[x + 1][y - 1] +
board[x + 1][y] +
board[x + 1][y + 1] - 8 * '0');
}
void Player(char board[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
int x, y;
int count = 0;
while (1)
{
printf("请排雷:\n");
scanf("%d %d", &x, &y);
if (x >= 1 && x <= 9 && y >= 1 && y <= 9)
{
if (board[x][y] == '0')
{
Openboard(show, board, x, y);
Displayboard(show, ROW, COL);
}
else if (board[x][y] == '1')
{
printf("你死了\n");
break;
}
}
else
{
printf("请重新输入");
}
int i, j;
for (i = 1; i <= row; i++)
{
for (j = 1; j <= col; j++)
{
if (show[i][j] == '*')
{
count++;
}
}
}
if (count == Easy_count)
{
printf("成功\n");
break;
}
}
}
void Openboard(char show[ROWS][COLS], char board[ROWS][COLS], int row, int col)
{
if (row >= 1 && row <= ROW && col >= 1 && col <= COL)
{
int count=sum(board, row, col);
if (count != 0)
{
show[row][col] = count + '0';
}
else if (show[row][col] != '_')
{
show[row][col] = '_';
int i = 0, j = 0;
for (i = row - 1; i <= row + 1; i++)
{
for (j = col - 1; j <= col + 1; j++)
{
Openboard(show, board, i,j);
}
}
}
else
{
return;
}
}
}
game.h
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#define ROW 9
#define COL 9
#define ROWS ROW+2
#define COLS COL+2
#define Easy_count 10
void Itnboard(char board[ROWS][COLS], int rows, int cols,char c);
void Displayboard(char board[ROWS][COLS], int row, int col);
void Setboard(char board[ROWS][COLS], int row, int col);
void Player(char board[ROWS][COLS], char show[ROWS][COLS], int row, int col);
void Openboard(char show[ROWS][COLS], char board[ROWS][COLS], int row, int col);
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