Python中的建造者模式：如何使用简单对象创建复杂对象？

class Product:
    def __init__(self):
        self.parts = []

    def add(self, part):
        self.parts.append(part)

    def list_parts(self):
        print(f"Product parts: {', '.join(self.parts)}")

class Builder:
    def build_part_a(self):
        pass

    def build_part_b(self):
        pass

    def build_part_c(self):
        pass

    def get_product(self):
        pass

class ConcreteBuilder1(Builder):
    def __init__(self):
        self.product = Product()

    def build_part_a(self):
        self.product.add("Part A1")

    def build_part_b(self):
        self.product.add("Part B1")

    def build_part_c(self):
        self.product.add("Part C1")

    def get_product(self):
        return self.product

class ConcreteBuilder2(Builder):
    def __init__(self):
        self.product = Product()

    def build_part_a(self):
        self.product.add("Part A2")

    def build_part_b(self):
        self.product.add("Part B2")

    def build_part_c(self):
        self.product.add("Part C2")

    def get_product(self):
        return self.product

class Director:
    def __init__(self, builder):
        self.builder = builder

    def build_minimal_product(self):
        self.builder.build_part_a()

    def build_full_product(self):
        self.builder.build_part_a()
        self.builder.build_part_b()
        self.builder.build_part_c()

def client_code(director: Director):
    builder = ConcreteBuilder1()
    director.builder = builder

    print("Minimal product:")
    director.build_minimal_product()
    builder.get_product().list_parts()

    print("Full product:")
    director.build_full_product()
    builder.get_product().list_parts()

if __name__ == "__main__":
    director = Director(ConcreteBuilder1())
    client_code(director)

    director = Director(ConcreteBuilder2())
    client_code(director)