使用Python 制作一个简单的计算器
要理解此示例,您应该了解以下Python 编程主题:
Python 函数
Python 函数参数
Python 用户定义函数
示例:使用函数的简单计算器
# Program make a simple calculator # This function adds two numbers def add(x, y): return x + y # This function subtracts two numbers def subtract(x, y): return x - y # This function multiplies two numbers def multiply(x, y): return x * y # This function divides two numbers def divide(x, y): return x / y print("Select operation.") print("1.Add") print("2.Subtract") print("3.Multiply") print("4.Divide") while True: # take input from the user choice = input("Enter choice(1/2/3/4): ") # check if choice is one of the four options if choice in ('1', '2', '3', '4'): num1 = float(input("Enter first number: ")) num2 = float(input("Enter second number: ")) if choice == '1': print(num1, "+", num2, "=", add(num1, num2)) elif choice == '2': print(num1, "-", num2, "=", subtract(num1, num2)) elif choice == '3': print(num1, "*", num2, "=", multiply(num1, num2)) elif choice == '4': print(num1, "/", num2, "=", divide(num1, num2)) # check if user wants another calculation # break the while loop if answer is no next_calculation = input("Let's do next calculation? (yes/no): ") if next_calculation == "no": break else: print("Invalid Input")
输出
Select operation. 1.Add 2.Subtract 3.Multiply 4.Divide Enter choice(1/2/3/4): 3 Enter first number: 15 Enter second number: 14 15.0 * 14.0 = 210.0 Let's do next calculation? (yes/no): no
在这个程序中,我们要求用户选择一个操作。选项 1、2、3 和 4 有效。如果给出任何其他输入,输入无效显示并循环继续,直到选择了一个有效选项。
取两个数字,并使用一个if...elif...else分支来执行特定的部分。用户定义函数add()、subtract()、multiply()和divide()评估各自的操作并显示输出。
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