是否使用变量匹配PRIG_MATCH?

2022-03-29 00:00:00 php preg-match

这是我想尝试做的事情。我想要一种简单的方法,只需添加新电子邮件,而不必让我的客户接触主代码。

$list= 'gmail|yahoo|aol'; 


$banned = '[w.-]+@((?!'.$list.').)[w.-]+.w{2,4}';

if ( isset($data['email']) && !preg_match($banned, $data['email']) )
{}

或者也许。是否包含指向文本文件的内容?其中列出了哪些域?


更新

以下是我的代码..

//Banned Domains
    $banned = 'mailexpire|spamtrail|0815';
    //


    //Emails    
    $email_list = '/^[w.-]+@((?!'.$banned.').)[w.-]+.w{2,4}$/';             
    if ( isset($data['email']) && preg_match($email_list, $data['email']) )
    {
        $response->addError('Email Addresses from this domain are not allowed, Please try a different email address', 'email');
    }

    else if ( isset($data['email']) && !preg_match($email_list, $data['email']) )
    {
        $query = SK_MySQL::placeholder("SELECT COUNT(`profile_id`) FROM `".TBL_PROFILE."` WHERE `email`='?'",$data['email']);
        if (SK_MySQL::query($query)->fetch_cell()) {
            $error_msg = SK_Language::text('%forms._fields.email.errors.already_exists');
            $response->addError($error_msg,'email');
        }
    }
    //END

出于某种原因..它没有捕获域?


解决方案

问题是您忘了放模式分隔符:

$banned = '/^[w.-]+@((?!' . $list . ').)[w.-]+.w{2,4}$/';

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