返回值的类型必须为?照明\数据库\查询\生成器,返回了App\Models\ModelName
我正在尝试获得以下响应:
"user": {
"id": 1,
"first_name": "john",
"last_name": "doe",
"email": "john@mail.com",
"phone_number": "12345678",
"email_verified_at": null,
"created_at": "2021-09-02T08:57:07.000000Z",
"updated_at": "2021-09-02T08:57:07.000000Z",
"country": {
"id": 1,
"name": "UK",
"phone_code": 44
}
}
而不是:
"user": {
"id": 1,
"first_name": "john",
"last_name": "doe",
"email": "omar.fd.du@gmail.com",
"phone_number": "12345678",
"email_verified_at": null,
"created_at": "2021-09-02T08:57:07.000000Z",
"updated_at": "2021-09-02T08:57:07.000000Z",
"country_id": 1
}
为此,我在用户模型中使用赋值函数:
public function getCountryIdAttribute(): Builder|null
{
return Country::where('id', $this->attributes['country_id'])
->get()
->first();
}
但是,已经在我正确设置其连接的外部数据库中找到了Countries表。
但我创建的国家/地区模型如下Laravel documentation:
use IlluminateDatabaseEloquentModel;
class Country extends Model
{
/**
* The database connection that should be used by the model.
*
* @var string
*/
protected $connection = 'my second db connection name';
/**
* The table associated with the model.
*
* @var string
*/
protected $table = 'countries';
/**
* The primary key associated with the table.
*
* @var string
*/
protected $primaryKey = 'id';
/**
* The model's default values for attributes.
*
* @var array
*/
protected $attributes = [
'id',
'name',
'phone_code',
];
}
当我尝试获取用户时,收到以下错误:
{
"error": [
"App\Models\User::getCountryIdAttribute(): Return value must be of type ?
Illuminate\Database\Query\Builder, App\Models\Country returned"
],
"message": "Unhandled server exception",
"code": 500
}
我试图尽可能多地解释我的情况。 感谢您的帮助。
解决方案
问题是您在函数getCountryIdAttribute
中说它返回Builder | null
。当您这样做时
return Country::where('id', $this->attributes['country_id'])
->get()
->first();
它将返回Country
或null
的实例。要解决问题,您应该将返回类型更新为Country | null
:
public function getCountryIdAttribute(): Country | null
{
return Country::where('id', $this->attributes['country_id'])
->get()
->first();
}
Laravel提供了使用relationships的方法,这将极大地提高您的代码性能。在这种情况下,您可以执行以下操作:
public function country()
{
return $this->hasOne(Country::class, 'country_id');
}
然后在获取users
时,您可以执行以下操作:
$users = User::where(...)->with('country')->get();
这将防止您的代码出现N+1问题。
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