使用array_diff(),如何从array2而不是array1中获取差异?

2022-01-25 00:00:00 arrays compare php array-difference

我正在尝试像这样使用 array_diff.这是我的两个数组输出:

I'm trying to use array_diff like so. Here are my two array outputs:

列表 1 输出

Array ([0] => 0022806 ) 

列表 2 输出

Array ([0] => 0022806 [1] => 0023199 ) 

PHP

$diff = array_diff($list_1, $list_2);

print "DIFF: " . count($diff) ."<br>";
print_r($diff);

输出是:

DIFF: 0
Array ( )

知道我做错了什么吗?为什么没有返回0023199?

Any idea what I'm doing wrong? Why is 0023199 not returned?

推荐答案

array_diff() 中参数的顺序很重要

The order of arguments in array_diff() is important

返回一个数组,其中包含 array1 中所有不属于存在于任何其他数组中

Returns an array containing all the entries from array1 that are not present in any of the other arrays

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