symfony2 教义 expr 子查询:错误:参数号无效
试图获得用户喜欢的状态.
公共函数 getLikedStatuses(User $user){$qb = $this->_em->createQueryBuilder();$qb->选择('s.id')->from('WallBundle:喜欢','l')->innerJoin('l.status', 's')->where('l.user = :user')->setParameter('user', $user)->orderBy('s.id','DESC');$qb2= $this->_em->createQueryBuilder()->选择('st')->from('WallBundle:Status','st');$qb2->andWhere($qb2->expr()->in('st.id',$qb->getDQL()));return $qb2->getQuery()->getResult();}
<块引用>
错误:无效的参数号:绑定变量的数量与标记的数量不匹配
顺便说一句:当我转储 $qb->getDQL() 时:
string 'SELECT s.id FROM TBWBundleEntityLikes l LEFT JOIN l.status s WHERE l.user = :user' (length=87)
BTW2:当我将 '$qb->getDQL()' 替换为 (12073)(状态 ID)时,它可以工作......
解决方案由于使用子查询时学说不支持限制(看看我的评论)一种可能的解决方案是执行两个单独的查询,这并不理想但有效.
/*** @param 用户 $user* @param int $limit* @param int $offset* @return 用户[]*/公共函数 getUserFollowers(用户 $user, $limit = 20, $offset = 0){$_followersIds = $this->getEntityManager()->createQueryBuilder()->select('IDENTITY(r.followeduser)')->from($this->getEntityName(), 'r')->where('r.followeeuser = :user')->andWhere('r.followeduser !=:user')->setParameter('user', $user)->orderBy('r.id', 'DESC')->setFirstResult($offset)->setMaxResults($limit)->getQuery()->getResult();$_usersQb = $this->getEntityManager()->createQueryBuilder();$_usersQb->选择('你')->from('UserBundle:User', 'u')->where('u.id IN (:followersIds)')->setParameter('followersIds', array_values($_followersIds));return $_usersQb->getQuery()->getResult();}
trying to get liked statuses by user.
public function getLikedStatuses(User $user)
{
$qb = $this->_em->createQueryBuilder();
$qb
->select('s.id')
->from('WallBundle:Likes','l')
->innerJoin('l.status', 's')
->where('l.user = :user')
->setParameter('user', $user)
->orderBy('s.id','DESC')
;
$qb2= $this->_em->createQueryBuilder()
->select('st')
->from('WallBundle:Status','st');
$qb2 ->andWhere($qb2->expr()->in('st.id',$qb->getDQL()));
return $qb2->getQuery()->getResult();
}
Error: Invalid parameter number: number of bound variables does not match number of tokens
BTW: when i dump the $qb->getDQL():
string 'SELECT s.id FROM TBWBundleEntityLikes l LEFT JOIN l.status s WHERE l.user = :user' (length=87)
BTW2: when i replace the '$qb->getDQL()' for (12073) (id of status) it works...
解决方案As doctrine doesn't support a limit when using subquery (look at my comment) one possible solution is to execute two separate queries which is not ideal but works.
/**
* @param User $user
* @param int $limit
* @param int $offset
* @return User[]
*/
public function getUserFollowers(User $user, $limit = 20, $offset = 0)
{
$_followersIds = $this->getEntityManager()
->createQueryBuilder()
->select('IDENTITY(r.followeduser)')
->from($this->getEntityName(), 'r')
->where('r.followeeuser = :user')
->andWhere('r.followeduser !=:user')
->setParameter('user', $user)
->orderBy('r.id', 'DESC')
->setFirstResult($offset)
->setMaxResults($limit)
->getQuery()
->getResult();
$_usersQb = $this->getEntityManager()->createQueryBuilder();
$_usersQb
->select('u')
->from('UserBundle:User', 'u')
->where('u.id IN (:followersIds)')
->setParameter('followersIds', array_values($_followersIds));
return $_usersQb->getQuery()->getResult();
}
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