PHP - 假时获取布尔以回显假
以下代码不打印任何内容:
The following code doesn't print out anything:
$bool_val = (bool)false;
echo $bool_val;
但是下面的代码打印出 1
:
But the following code prints 1
:
$bool_val = (bool)true;
echo $bool_val;
当 $bool_val
为 false
时,有没有比添加 0
或 false
更好的方法来打印code>if 语句?
Is there a better way to print 0
or false
when $bool_val
is false
than adding an if
statement?
推荐答案
echo $bool_val ? 'true' : 'false';
或者如果你只想在它为假时输出:
Or if you only want output when it's false:
echo !$bool_val ? 'false' : '';
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