如果行存在，则更新 MySQL 表的最快方法，否则插入.超过 2 个非唯一键

2022-01-17 00:00:00 sql-update sql php mysql sql-insert

我的表结构如下:

 CREATE TABLE IF NOT EXISTS `reports` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `day` int(11) NOT NULL,
  `uid` int(11) NOT NULL,
  `siteid` int(11) NOT NULL,
  `cid` int(3) NOT NULL,
  `visits` int(11) NOT NULL,
  PRIMARY KEY (`id`)
 )

目前我检查 &使用以下代码段插入/更新:

Currently i check & insert/update with the following snippet:

 $checkq = mysql_query("SELECT count(*) as rowexist FROM reports WHERE day='$day' AND uid='$uid' AND siteid='$sid' AND cid='$cid'") or die(mysql_error()); 
$checkr = mysql_fetch_array($checkq);

if ($checkr['rowexist'] > 0) {
 mysql_query("UPDATE reports_adv SET visits=visits+1 WHERE  day='$day' AND uid='$uid' AND siteid='$sid' AND cid='$cid'"); 
} else {
 mysql_query("INSERT INTO reports_adv SET day='$day', uid='$uid', siteid='$sid', cid='$cid', visits='1'");
}

如果行存在，否则使用超过 2 个非唯一键插入是否是更新此 MySQL 表的最快方法?

Is a fastest way to update this MySQL table if row exists else insert with more than 2 non-unique keys?

推荐答案

只需使用 INSERT...ON DUPLICATE KEY UPDATE

INSERT INTO reports_adv (day, uid, siteid, cid, visits) 
VALUES ('$day', '$uid', '$sid', '$cid', 1)
ON DUPLICATE KEY UPDATE visits=visits+1;

  • INSERT ... ON DUPLICATE KEY UPDATE语法

    但在此之前，您应该在列上定义 UNIQUE 约束.

    but before anything else, you should define a UNIQUE constraint on the columns.

    ALTER TABLE reports_adv  ADD CONSTRAINT tb_uq UNIQUE (day, uid, siteid, cid)

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