PHP:在单个查询中更新多个 MySQL 字段
我基本上只是想更新表中的多个值.解决此问题的最佳方法是什么?这是当前代码:
I am basically just trying to update multiple values in my table. What would be the best way to go about this? Here is the current code:
$postsPerPage = $_POST['postsPerPage'];
$style = $_POST['style'];
mysql_connect ("localhost", "user", "pass") or die ('Error: ' . mysql_error());
mysql_select_db ("db");
mysql_query("UPDATE settings SET postsPerPage = $postsPerPage WHERE id = '1'") or die(mysql_error());
我想包含的另一个更新是:
The other update I want to include is:
mysql_query("UPDATE settings SET style = $style WHERE id = '1'") or die(mysql_error());
谢谢！
推荐答案
使用逗号分隔添加多个列:
Add your multiple columns with comma separations:
UPDATE settings SET postsPerPage = $postsPerPage, style= $style WHERE id = '1'
但是，您没有清理您的输入?这意味着任何随机黑客都可能破坏您的数据库.看到这个问题:什么是清理用户输入的最佳方法用 PHP 吗?
However, you're not sanitizing your inputs?? This would mean any random hacker could destroy your database. See this question: What's the best method for sanitizing user input with PHP?
另外，样式是数字还是字符串?我假设一个字符串，所以它需要被引用.
Also, is style a number or a string? I'm assuming a string, so it would need to be quoted.
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