PHP: intval() 等价于数字 >= 2147483647
在 PHP 5 中,每当我将数字作为输入时,我都会使用 intval().这样,我想确保我没有得到字符串或浮点数.我的输入数字应该都是整数.但是当我得到数字 >= 2147483647 时,就超过了有符号整数限制.
In PHP 5, I use intval() whenever I get numbers as an input. This way, I want to ensure that I get no strings or floating numbers. My input numbers should all be in whole numbers. But when I get numbers >= 2147483647, the signed integer limit is crossed.
如何为所有大小的数字设置一个等效的 intval()?
What can I do to have an intval() equivalent for numbers in all sizes?
这是我想要的:
<?php
$inputNumber = 3147483647.37;
$intNumber = intvalEquivalent($inputNumber);
echo $intNumber; // output: 3147483647
?>
非常感谢您!
根据一些答案,我尝试编写等效函数.但它还不能像 intval() 那样工作.我该如何改进它?它有什么问题?
Based on some answers, I've tried to code an equivalent function. But it doesn't work exactly as intval() does yet. How can I improve it? What is wrong with it?
function intval2($text) {
$text = trim($text);
$result = ctype_digit($text);
if ($result == TRUE) {
return $text;
}
else {
$newText = sprintf('%.0f', $text);
$result = ctype_digit($newText);
if ($result == TRUE) {
return $newText;
}
else {
return 0;
}
}
}
推荐答案
试试这个功能,它会像 intval 一样正确删除任何小数,并删除所有非数字字符.
Try this function, it will properly remove any decimal as intval does and remove any non-numeric characters.
<?php
function bigintval($value) {
$value = trim($value);
if (ctype_digit($value)) {
return $value;
}
$value = preg_replace("/[^0-9](.*)$/", '', $value);
if (ctype_digit($value)) {
return $value;
}
return 0;
}
// SOME TESTING
echo '"3147483647.37" : '.bigintval("3147483647.37")."<br />";
echo '"3498773982793749879873429874.30872974" : '.bigintval("3498773982793749879873429874.30872974")."<br />";
echo '"hi mom!" : '.bigintval("hi mom!")."<br />";
echo '"+0123.45e6" : '.bigintval("+0123.45e6")."<br />";
?>
这是生成的输出:
"3147483647.37" : 3147483647
"3498773982793749879873429874.30872974" : 3498773982793749879873429874
"hi mom!" : 0
"+0123.45e6" : 0
希望有帮助!
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