获取当前 URL/URI 而不使用某些 $_GET 变量
如何在 Yii 中获取当前页面的 URL.例如:
How, in Yii, to get the current page's URL. For example:
http://www.yoursite.com/your_yii_application/?lg=pl&id=15
但不包括 $GET_['lg']
(不手动解析字符串)?
but excluding the $GET_['lg']
(without parsing the string manually)?
我的意思是,我正在寻找类似于 Yii::app()->requestUrl
/Chtml::link()
方法的东西,用于返回URL 减去一些 $_GET
变量.
I mean, I'm looking for something similar to the Yii::app()->requestUrl
/ Chtml::link()
methods, for returning URLs minus some of the $_GET
variables.
编辑:当前解决方案:
unset $_GET['lg'];
echo Yii::app()->createUrl(
Yii::app()->controller->getId().'/'.Yii::app()->controller->getAction()->getId() ,
$_GET
);
推荐答案
Yii 1
Yii::app()->request->url
对于 Yii2:
Yii::$app->request->url
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