Symfony2.1 映射错误:class_parents()
我在尝试使用 Symfony2.1 项目中的 Doctrine2 从表(通过实体)获取数据时遇到问题.这是我得到错误的控制器:
I have a problem trying to get data from a table (via entity) using Doctrine2 in a Symfony2.1 project. Here is the controller where I get the error:
/**
* Country list
*/
public function countrylistAction()
{
$em = $this->getDoctrine()->getManager();
$countryList = $em->getRepository('ProjectBaseBundle:SYS_TCountry')
->findAll();
$serializer = new Serializer(array(new GetSetMethodNormalizer()),
array('json' => new JsonEncoder()));
return new Response($serializer->serialize($countryList, 'json'));
}
实体:
<?php
namespace CompanyProjectBaseBundleEntity;
use DoctrineORMMapping as ORM;
use SymfonyComponentValidatorConstraints as Assert;
/**
* @ORMEntity
* @ORMTable(name="SYS_TCountry")
*/
class SYS_TCountry
{
/**
* @ORMId
* @ORMColumn(type="string", length=3, nullable=false)
* @var string
*/
protected $idcountry;
/**
* @ORMColumn(type="string", length=75, nullable=false)
* @AssertNotBlank()
* @var string
*/
protected $name;
....
public function getIdcountry() { return $this->idcountry; }
public function getName() { return $this->name; }
public function getA2() { return $this->a2; }
public function getA3() { return $this->a3; }
public function getIdstatus() { return $this->idstatus; }
public function setIdcountry($idcountry) { $this->idcountry = $idcountry; }
public function setName($name) { $this->name = $name; }
public function setA2($a2) { $this->a2 = $a2; }
public function setA3($a3) { $this->a3 = $a3; }
public function setIdstatus($idstatus) { $this->idstatus = $idstatus; }
public function __toString() { return $this->idcountry; }
}
Config.yml:
Config.yml:
# Doctrine Configuration
doctrine:
dbal:
driver: %database_driver%
host: %database_host%
port: %database_port%
dbname: %database_name%
user: %database_user%
password: %database_password%
charset: UTF8
orm:
auto_generate_proxy_classes: %kernel.debug%
auto_mapping: true
这是错误:
Warning: class_parents():
Class CompanyProjectBaseBundleEntitySYS_TCountry does not exist and could not be loaded in
/var/www/project/src/vendor/doctrine/common/lib/Doctrine/Common/Persistence/Mapping/RuntimeReflectionService.php line 40
这很奇怪，因为正如 Doctrine 在控制台中所说，映射已正确完成:我测试它执行 php app/console dictionary:mapping:info:
It is strange because, as Doctrine says in console, the mapping is properly done: I test it executing php app/console doctrine:mapping:info:
[OK] CompanyProjectBaseBundleEntitySYS_TCountry
如果我在控制台中执行查询一切正常 -> 应用程序/控制台原则:查询:sql 'SELECT * FROM SYS_TCountry'，返回结果.
and if I execute a query in console everything goes fine -> app/console doctrine:query:sql 'SELECT * FROM SYS_TCountry', that return results.
我不知道是否使用 Symfony2.1 我必须配置一些与 2.0 版本不同的东西，但似乎相同，因为映射是 Doctrine 责任.
I do not know if using Symfony2.1 I have to configure something different to the 2.0 version, but seems the same because the mapping is Doctrine responsibility.
推荐答案
Symfony 遵循 PSR-0 文件名标准.这意味着如果你在类名中使用下划线，在决定你的类应该放在哪里时，它将用目录分隔符替换它，如下所示:
Symfony follows the PSR-0 standard for filenames. That, amongst other things, means that if you use an underscore in your class name, it will replace it with a directory separator when deciding where your class should live, like this:
amespacepackageClass_Name => /path/to/project/lib/vendor/namespace/package/Class/Name.php
所以，如果你有一个名为 SYS_TCountry 的类，它会期望在
So, if you have a class named SYS_TCountry it would expect to find it in
Company/Project/BaseBundle/Entity/SYS/TCountry.php
而不是
Company/Project/BaseBundle/Entity/SYS_TCountry.php
我认为最好的解决方案是将文件名和类名更改为 SYSTCountry.您无需更改表名.
I think that your best solution would be to change the filename and class name to SYSTCountry. You don´t need to change the table name.
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