Symfony 2 Doctrine 导出到 JSON

2022-01-16 00:00:00 json web-services php symfony doctrine

我正在使用 Symfony 2 和 Doctrine 2 为 iOS 应用程序创建 Web 服务 (JSON).

I'm using Symfony 2 with Doctrine 2 to create a web service(JSON) for an iOS app.

要获取我的实体，我会这样做:

To fetch my entity i do:

$articles = $this->getDoctrine()->getRepository('UdoPaddujourBundle:MenuArticle')->findAll();

我必须告诉你:

$article = array();
$article = $articles->toArray();

给我以下错误:

Fatal error: Call to a member function toArray() on a non-object

同样的事情发生在

$article = $articles->exportTo('json');

<小时>

如何创建 json 响应?

How can i create a json response ?

亲切的问候，卡瑙丹

var_dump($articles) =

var_dump($articles) = 

array(18) {
   [0]=>
     object(UdoPaddujourBundleEntityMenuArticle)#50 (4) {
    ["id":"UdoPaddujourBundleEntityMenuArticle":private]=>
    int(1)
    ["name":"UdoPaddujourBundleEntityMenuArticle":private]=>
    string(17) "My Article Name 1"
    ["description":"UdoPaddujourBundleEntityMenuArticle":private]=>
    string(26) "My Article Description 1"
    ["price":"UdoPaddujourBundleEntityMenuArticle":private]=>
    float(20)
    }
   [1]=> ...

- 稍后编辑

如何遍历所有属性名称"?这就是我所拥有的:

- LATER EDIT

How can i loop through all the "property names" ? This is what i've got:

$myarray=array(); 
$myArray["name"]=array(); 
$myArray["description"]=array(); 
foreach($articles in $article) 
{ 
  array_push($myArray["name"], $article->getName());
  array_push($myArray["description"], $article->getDescription()); 
}

推荐答案

如果你使用学说查询，你也可以这样做:

If you use a doctrine query you can also do this:

$em = $this->getDoctrine()->getEntityManager();
$query = $em->createQuery('SELECT ma FROM UdoPaddujourBundle:MenuArticle ma ...etc');
$myArray = $query->getArrayResult();

然后使用 json_encode($myArray);

参见 这里了解更多详情.

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