如何加载使用 PHP 生成的 SVG 文件?

2022-01-14 00:00:00 xampp svg php apache

我想用 PHP 创建一个 SVG 文件,然后将它包含在一个 HTML 文件中.这是我到目前为止所拥有的(遵循 本教程)

I want to create a SVG file with PHP, and then include it in a HTML file. Here's what I have so far (following this tutorial)

svg.php:

<?php
header("Content-type: image/svg+xml");
?>
<?xml version="1.0" encoding="iso-8859-1"?>
<!DOCTYPE svg PUBLIC "-//W3C//DTD SVG 1.0//EN"
"http://www.w3.org/TR/2001/
REC-SVG-20010904/DTD/svg10.dtd">

<svg width="310" height="140" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink">
    <g style="stroke:black;fill:lightgreen" transform="translate(30,30)">
        <rect x="10" y="10" width="100" height="30" style="stroke-width:4"/>
        <circle cx="170" cy="25" r="20" style="stroke-width:4"/>
        <line x1="265" y1="10" x2="200" y2="70" style="stroke-width:4"/>
        <text x="80" y="90" style="font:size: 8">Basic shapes</text>
    </g>
</svg>

index.html

<!DOCTYPE html>
<html>
<head>
<style type="text/css">
html,body, #MOSVG { 
    height: 100%; 
    width: 100%;
    padding:0;
    margin:0;
}
</style>
</head>
<body>
    <object data="svg.php" type="image/svg+xml" id="MOSVG" />

</body>
</html>

当我查看 index.html 时,我看到的只是一个空白页.控制台上没有警告/错误.Apache 错误日志(我正在使用 XAMPP)给出 [Mon Jul 09 14:36:15 2012] [error] [client 127.0.0.1] script 'C:/xampp/htdocs/svgtest/public/svg.php' 未找到或无法统计,引用者:http://localhost/svgtest/public/.它们在同一个目录中.

When I look at index.html all I see is a blank page. There's no warnings/errors on the console. Apache error logs (I'm using XAMPP) give [Mon Jul 09 14:36:15 2012] [error] [client 127.0.0.1] script 'C:/xampp/htdocs/svgtest/public/svg.php' not found or unable to stat, referer: http://localhost/svgtest/public/. They're in the same directory.

推荐答案

GeoPhoenix 在上面回答了,我想我会把它放到一个答案中,以便有一个官方的:

GeoPhoenix answered above, I figured I'd put it into an answer so that there's an offical one:

如果您删除 <?xml?> 行,它会呈现 svg

if you remove the <?xml?> line it renders the svg

由于 short-open-tag 设置(感谢 fvu).这是一个简单的修复,我刚刚替换了

PHP can see <? as the opening tag for PHP code (rather than an XML declaration), thanks to the short-open-tag setting (thanks to fvu). This is an easy fix, I just replaced

<?xml version="1.0" encoding="iso-8859-1"?>

<?php echo '<?xml version="1.0" encoding="iso-8859-1"?>';?>

这具有相同的预期结果并且不会导致语法错误.

This has the same intended result and doesn't cause syntax errors.

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