如何防止 PHP 脚本多次运行?
目前,我试图阻止 onlytask.php
脚本多次运行:
Currently, I tried to prevent an onlytask.php
script from running more than once:
$fp = fopen("/tmp/"."onlyme.lock", "a+");
if (flock($fp, LOCK_EX | LOCK_NB)) {
echo "task started
";
//
while (true) {
// do something lengthy
sleep(10);
}
//
flock($fp, LOCK_UN);
} else {
echo "task already running
";
}
fclose($fp);
并且有一个cron作业每分钟执行一次上述脚本:
and there is a cron job to execute the above script every minute:
* * * * * php /usr/local/src/onlytask.php
它工作了一段时间.几天后,当我这样做时:
It works for a while. After a few day, when I do:
ps auxwww | grep onlytask
我发现有 两个 实例正在运行!不是三个或更多,不是一个.我杀死了其中一个个体.几天后,又有两个实例.
I found that there are two instances running! Not three or more, not one. I killed one of the instances. After a few days, there are two instances again.
代码有什么问题?是否有其他替代方法可以限制 onlytask.php 的一个实例正在运行?
What's wrong in the code? Are there other alternatives to limit only one instance of the onlytask.php is running?
附言我的 /tmp/
文件夹未清理.ls -al/tmp/*.lock
显示锁定文件是在第一天创建的:
p.s. my /tmp/
folder is not cleaned up. ls -al /tmp/*.lock
show the lock file was created in day one:
-rw-r--r-- 1 root root 0 Dec 4 04:03 onlyme.lock
推荐答案
现在我通过 ps
检查进程是否正在运行,并通过 bash
脚本扭曲 php 脚本:
Now I check whether the process is running by ps
and warp the php script by a bash
script:
#!/bin/bash
PIDS=`ps aux | grep onlytask.php | grep -v grep`
if [ -z "$PIDS" ]; then
echo "Starting onlytask.php ..."
php /usr/local/src/onlytask.php >> /var/log/onlytask.log &
else
echo "onlytask.php already running."
fi
并通过 cron
每分钟运行一次 bash
脚本.
and run the bash
script by cron
every minute.
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