php domdocument获取属性值所在的节点值

2022-01-13 00:00:00 attributes php domdocument nodevalue

假设我的 XML 如下所示:

Say my XML looks like this:

<record>
  <row name="title">this item</row>
  <row name="url">this url</row>
</record>

现在我正在做这样的事情:

Now I'm doing something like this:

$xml = new DOMDocument();
$xml->load('xmlfile.xml');

echo $xml->getElementByTagName('row')->item(0)->attributes->getNamedItem('title')->nodeValue;

但这只是给了我:

注意:试图获取非对象 id 的属性

NOTICE: Trying to get property of non-object id

有人知道如何获取name"属性值为title"的节点值吗?

Does anybody know how to get the node value where the "name" attribute has value "title"?

推荐答案

试试:

$xml = new DOMDocument();
$xml->loadXml('
<record>
  <row name="title">this item</row>
  <row name="url">this url</row>
</record>
');

$xpath = new DomXpath($xml);

// traverse all results
foreach ($xpath->query('//row[@name="title"]') as $rowNode) {
    echo $rowNode->nodeValue; // will be 'this item'
}

// Or access the first result directly
$rowNode = $xpath->query('//row[@name="title"][1]')->item(0);
if ($rowNode instanceof DomElement) {
    echo $rowNode->nodeValue;
}

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