如何在 Laravel Eloquent 查询(或使用查询生成器)中为表起别名?
假设我们正在使用 Laravel 的查询构建器:
$users = DB::table('really_long_table_name')->select('really_long_table_name.id')->get();
我正在寻找与此 SQL 等效的方法:
really_long_table_name AS short_name
当我必须输入大量选择和位置时,这将特别有用(或者通常我在选择的列别名中也包含别名,并且它在结果数组中使用).没有任何表格别名,我的打字量会增加很多,而且一切都变得不那么可读了.在 laravel 文档中找不到答案,有什么想法吗?
解决方案Laravel 支持 AS
表和列的别名.试试
$users = DB::table('really_long_table_name AS t')->select('t.id AS uid')->get();
让我们用一个很棒的 tinker
工具来看看它的实际效果
Lets say we are using Laravel's query builder:
$users = DB::table('really_long_table_name')
->select('really_long_table_name.id')
->get();
I'm looking for an equivalent to this SQL:
really_long_table_name AS short_name
This would be especially helpful when I have to type a lot of selects and wheres (or typically I include the alias in the column alias of the select as well, and it get's used in the result array). Without any table aliases there is a lot more typing for me and everything becomes a lot less readable. Can't find the answer in the laravel docs, any ideas?
解决方案Laravel supports aliases on tables and columns with AS
. Try
$users = DB::table('really_long_table_name AS t')
->select('t.id AS uid')
->get();
Let's see it in action with an awesome tinker
tool
$ php artisan tinker [1] > Schema::create('really_long_table_name', function($table) {$table->increments('id');}); // NULL [2] > DB::table('really_long_table_name')->insert(['id' => null]); // true [3] > DB::table('really_long_table_name AS t')->select('t.id AS uid')->get(); // array( // 0 => object(stdClass)( // 'uid' => '1' // ) // )
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