Yii2 QueryBuilder 更新与加入
我有以下原始 SQL 查询:
I have the following raw SQL query:
UPDATE `pay_audit`
JOIN `invoice_items`
ON `invoice_items`.`mdn` = `pay_audit`.`account_id`
AND `invoice_items`.`unitprice` = `pay_audit`.`payment`
AND `invoice_items`.`producttype_name` LIKE 'PAYMENT'
AND DATE_FORMAT(`invoice_items`.`created`, '%Y-%m-%d') = '2015-02-21'
SET `pay_audit`.`invoice_item_id` = `invoice_items`.`id`
WHERE `pay_audit`.`report_date` = '2015-02-21'
日期是php中的变量$date.
The date is a variable $date in php.
如何将这个原始 SQL 查询转换"为 Yii2 QueryBuilder?
How can i "convert" this raw SQL query into Yii2 QueryBuilder?
[更新]
正如 Felipe 提到的,查询构建器是不可能的,所以我最终这样做了:
As Felipe mentioned it's not possible with query builder so i ended up doing it like followed:
$today = date('Y-m-d');
$sql = "";
$sql .= "UPDATE `pay_audit` ";
$sql .= "JOIN `invoice_items` ";
$sql .= "ON `invoice_items`.`mdn` = `pay_audit`.`account_id` ";
$sql .= "AND `invoice_items`.`unitprice` = `qpay_audit`.`payment` ";
$sql .= "AND `invoice_items`.`producttype_name` LIKE 'PAYMENT' ";
$sql .= "AND DATE_FORMAT(`invoice_items`.`created`, '%Y-%m-%d') = '$today' ";
$sql .= "SET `pay_audit`.`invoice_item_id` = `invoice_items`.`id` ";
$sql .= "WHERE `pay_audit`.`report_date` = '$today'";
$command = Yii::$app->db->createCommand($sql);
$command->execute();
推荐答案
我很害怕 Yii 2 查询生成器 仅用于选择查询.
对于更新查询,您至少有三个选项:
For update queries you have at least three options:
原始 SQL:
Raw SQL:
Yii::$app->db->createCommand('update user set status = 1 where age > 30')->execute();
带有占位符的原始 SQL(防止 SQL 注入)
Raw SQL with placeholders (to prevent SQL injection)
Yii::$app->db->createCommand('update user set status = :status where age > 30')->bindValue(':status','1')->execute();
update() 方法
update() method
// update user set status = 1 where age > 30
Yii::$app->db->createCommand()->update('user', ['status' => 1], 'age > 30')->execute();
更多信息在这里:
Yii DAO
关于 SO 的另一个问题
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