如何在表单加载时检查 Yii2.0 CheckboxList 项目?

2022-01-07 00:00:00 php yii2

我正在尝试在 YII 2.0 框架中使用 Activeform 复选框列表小部件

I am trying to use a Activeform checkboxlist widget in YII 2.0 Framework

就我而言,我有一个名为list"的数组,其中包含将呈现为复选框列表的语言名称,现在我可以这样做,但我希望在表单加载时选中复选框.

in my case, i have an array called "list" which has the names of languages which will be rendered out as checkboxlist, now i am able to do that, but i want the check boxes to be checked as the form loads.

$list = [0 => 'PHP', 1 => 'MySQL', 2 => 'Javascript'];
$list2 = [0,2];

使用以下行,我可以使用 HTML 帮助类实现我想要的:

using the following line, i am able to acheive what i want using HTML helper classes :

<?= Html::checkboxList('CuisineId',$list2,$list); ?>

但我希望能够使用 Activeform Widget CheckboxList 来做到这一点,根据 文档 的使用方式如下:

but i want to be able to do this using the Activeform Widget CheckboxList, which as per documentation is to be used in the following way :

静态复选框列表( $items, $options = [] )

static checkboxList( $items, $options = [] )

所以就我而言,我想出了如何为 $items 传递参数,方法如下:

So in my case, i have figured how to pass the parameter for $items, which is in the following way:

<?= $form->field($record, 'CuisineId')->checkboxlist($list);?> 

但现在我不知道如何传递允许检查复选框的参数.

But now i do not know how to pass the parameters that will allow the checkboxes to be checked.

推荐答案

好的,我从 yiiframework 论坛 本身.

解决方案只是添加以下代码行并且它起作用了!:

The solution was just to add the following line of code and it worked! :

$record->CuisineId = $list2;

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