PHP 错误警告:参数 1 应为参考
我熟悉"PHP，我朋友的网站因错误而损坏:
I am "familiar" with PHP and my friend had his site broken with error:
Warning: Parameter 1 to Some_function_name() expected to be a reference,
value given in /.../public_html/includes/tng/tNG.class.php on line 219
第 219 行:
$ret = call_user_func_array($callBackFunction,$tempParam);
我不确定他的服务器上发生了什么，但托管公司团队说了一些关于 Joomla 和 PHP 冲突的内容.我该如何解决?
I am not sure what happened on his server, but hosting company team said something about the Joomla and PHP conflict. How can I fix it?
推荐答案
检查Some_Function_name()的函数签名，你可能有这样的:
Check the function signature of Some_Function_name(), you probably have something like:
function Some_Function_name(&$param1)
{
// ...
这是一个 PHP 5.3 兼容性问题.您可以从参数 $param1 中删除引用运算符 &.或者，如果绝对必要，您可以回滚到 PHP 5.2.x.
This is a PHP 5.3 compatibility issue. You could remove the reference operator & from the argument $param1. Or you could rollback to PHP 5.2.x if absolutely necessary.
相关文章