PHP GuzzleHttp.如何使用参数进行发布请求?
如何使用 GuzzleHttp(5.0 版)发出 post 请求.
How to make a post request with GuzzleHttp( version 5.0 ).
我正在尝试执行以下操作:
I am trying to do the following:
$client = new GuzzleHttpClient();
$client->post(
'http://www.example.com/user/create',
array(
'email' => 'test@gmail.com',
'name' => 'Test user',
'password' => 'testpassword'
)
);
但我收到错误:
PHP 致命错误:未捕获的异常InvalidArgumentException",消息为No method can handle the email config key"
PHP Fatal error: Uncaught exception 'InvalidArgumentException' with the message 'No method can handle the email config key'
推荐答案
试试这个
$client = new GuzzleHttpClient();
$client->post(
'http://www.example.com/user/create',
array(
'form_params' => array(
'email' => 'test@gmail.com',
'name' => 'Test user',
'password' => 'testpassword'
)
)
);
相关文章