如何在 PHP 中获取请求内容(正文)?
我正在向内容中包含 XML 的 php 服务器发送请求:
I am sending a request to a php server with a XML in the content:
POST /index3.php HTTP/1.0
Connection: Close
Accept: application/xml
Content-Type: text/xml
<?xml version="1.0" encoding="UTF-8"?>
<root />
我已经检查了全局变量(例如 $_GET、$_POST、$_ENV、$_FILES>, $_REQUEST...) 但它们都是空的.
I've checked in globals vars (like $_GET, $_POST, $_ENV, $_FILES, $_REQUEST...) but they are all empty.
如何检索服务器中的内容?
How could I retrieve the content in the server?
推荐答案
试试这个
$xml = file_get_contents('php://input');
来自手册:
php://input 是一个只读流，允许您从请求正文中读取原始数据.
php://input is a read-only stream that allows you to read raw data from the request body.
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