带有 GET 请求的 PHP 开关
我正在为我的网站构建一个简单的管理区域,我希望 URL 看起来像这样:
I am building a simple admin area for my site and I want the URLs to look somewhat like this:
http://mysite.com/admin/?home
http://mysite.com/admin/?settings
http://mysite.com/admin/?users
但我不确定如何检索请求的页面,然后显示所需的页面.我在我的交换机上试过这个:
But I am not sure how I would retrieve what page is being requested and then show the required page. I tried this in my switch:
switch($_GET[])
{
case 'home':
echo 'admin home';
break;
}
但我收到此错误:
致命错误:第 40 行无法使用 [] 读取 C:path owebdirectoryadminindex.php
有什么办法可以解决这个问题吗?我想避免为 GET 请求设置值,例如:
Is there any way around this? I want to avoid setting a value to the GET request, like:
http://mysite.com/admin/?action=home
如果你知道我的意思.谢谢.:)
If you know what I mean. Thanks. :)
推荐答案
使用 $_SERVER['QUERY_STRING']
–包含 ?
之后的位:
Use $_SERVER['QUERY_STRING']
– that contains the bits after the ?
:
switch($_SERVER['QUERY_STRING']) {
case 'home':
echo 'admin home';
break;
}
您可以更进一步地使用此方法并使用如下网址:
You can take this method even further and have URLs like this:
http://mysite.com/admin/?users/user/16/
只需使用 explode()
将查询字符串拆分为段,获取第一个并将其余部分作为方法的参数传递:
Just use explode()
to split the query string into segments, get the first one and pass the rest as arguments for the method:
$args = explode('/', rtrim($_SERVER['QUERY_STRING'], '/'));
$method = array_shift($args);
switch($method) {
case 'users':
$user_id = $args[2];
doSomething($user_id);
break;
}
这种方法在许多采用 MVC 模式的框架中都很流行.完全摆脱 ?
的另一个步骤是在 Apache 服务器上使用 mod_rewrite
,但我认为这有点超出了这个问题的范围.
This method is popular in many frameworks that employ the MVC pattern. An additional step to get rid of the ?
altogether is to use mod_rewrite
on Apache servers, but I think that's a bit out of scope for this question.
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