使用php获取html标签中的内容并在处理后替换它

2022-01-04 00:00:00 get php html

我有一个这样的 html (sample.html):

<头><身体><div id="内容"><!--内容--><p>一些内容</p><!--内容-->

如何使用 php 获取位于 2 个 html 注释 '' 之间的内容部分?我想得到那个，做一些处理然后放回去，所以我必须得到和放！可能吗?

解决方案

esafwan - 您可以使用正则表达式来提取 div(特定 id)之间的内容.

我之前为图片标签做过这件事，所以同样的规则也适用.我会查看代码并稍后更新消息.

[更新]试试这个:

]*'.$attr.'="'.$value.'">(.*?)<\/div>/si';preg_match($tag_regex,$xml,$匹配);返回 $matches[1];}$yourentirehtml = file_get_contents("test.html");$extract = get_tag('id', 'content', $yourentirehtml);回声 $extract;?>

或者更简单:

preg_match("/
]*id="content">(.*?)<\/div>/si", $text, $match);$content = $match[1];

吉姆

I have an html (sample.html) like this:

<html>
<head>
</head>
<body>
<div id="content">
<!--content-->

<p>some content</p>

<!--content-->
</div>
</body>
</html>

How do i get the content part that is between the 2 html comment '' using php? I want to get that, do some processing and place it back, so i have to get and put! Is it possible?

解决方案

esafwan - you could use a regex expression to extract the content between the div (of a certain id).

I've done this for image tags before, so the same rules apply. i'll look out the code and update the message in a bit.

[update] try this:

<?php
    function get_tag( $attr, $value, $xml ) {

        $attr = preg_quote($attr);
        $value = preg_quote($value);

        $tag_regex = '/<div[^>]*'.$attr.'="'.$value.'">(.*?)<\/div>/si';

        preg_match($tag_regex,
        $xml,
        $matches);
        return $matches[1];
    }

    $yourentirehtml = file_get_contents("test.html");
    $extract = get_tag('id', 'content', $yourentirehtml);
    echo $extract;
?>

or more simply:

preg_match("/<div[^>]*id="content">(.*?)<\/div>/si", $text, $match);
$content = $match[1];

jim

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