获取 youtube 视频 ID 为 PHP

2022-01-04 00:00:00 youtube url get php parse-url

我目前正在编写一个 web 应用程序，其中一些页面严重依赖于能够将正确的 youtube 视频拉入并播放.youtube URL 由用户提供，因此通常会带有变体，其中之一可能如下所示:

I am currently writing a webapp in which some pages are heavily reliant on being able to pull the correct youtube video in - and play it. The youtube URLS are supplied by the users and for this reason will generally come in with variants one of them may look like this:

http://www.youtube.com/watch?v=y40ND8kXDlg

而另一个可能看起来像这样:

while the other may look like this:

http://www.youtube.com/watch/v/y40ND8kXDlg

目前我可以使用以下代码从后者中提取 ID:

Currently I am able to pull the ID from the latter using the code below:

function get_youtube_video_id($video_id)
{

    // Did we get a URL?
    if ( FALSE !== filter_var( $video_id, FILTER_VALIDATE_URL ) )
    {

        // http://www.youtube.com/v/abcxyz123
        if ( FALSE !== strpos( $video_id, '/v/' ) )
        {
            list( , $video_id ) = explode( '/v/', $video_id );
        }

        // http://www.youtube.com/watch?v=abcxyz123
        else
        {
            $video_query = parse_url( $video_id, PHP_URL_QUERY );
            parse_str( $video_query, $video_params );
            $video_id = $video_params['v'];
        }

    }

    return $video_id;

}

如何处理使用 ?v 版本而不是 /v/ 版本的 URL?

How can I deal with URLS that use the ?v version rather than the /v/ version?

推荐答案

像这样:

$link = "http://www.youtube.com/watch?v=oHg5SJYRHA0";
$video_id = explode("?v=", $link);
$video_id = $video_id[1];

这是通用的解决方案:

$link = "http://www.youtube.com/watch?v=oHg5SJYRHA0&lololo";
$video_id = explode("?v=", $link); // For videos like http://www.youtube.com/watch?v=...
if (empty($video_id[1]))
    $video_id = explode("/v/", $link); // For videos like http://www.youtube.com/watch/v/..

$video_id = explode("&", $video_id[1]); // Deleting any other params
$video_id = $video_id[0];

或者只是使用这个正则表达式:

Or just use this regex:

(?v=|/v/)([-a-zA-Z0-9]+)

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