使用带有参数的 file_get_contents 从 PHP 获取请求

2022-01-04 00:00:00 http get php file-get-contents

我想向外部站点发送GET请求，但也想发送一些参数

I want to send a GET request to an external site, but also want to send some parameters

例如，我必须向 example.com 发送获取请求

for example i've to send a get request to example.com

我想执行 www.example.com/send.php?uid=1&pwd=2&msg=3&phone=3&provider=xyz

i want to execute www.example.com/send.php?uid=1&pwd=2&msg=3&phone=3&provider=xyz

我的代码是:

$getdata = http_build_query(
array(
    'uid' => '1',
    'pwd' => '2',
 'msg'=>'3',
 'phone'=>'9999',
 'provider'=>'xyz'
 )
);

$opts = array('http' =>
 array(
    'method'  => 'GET',
    'content' => $getdata
)
);

$context  = stream_context_create($opts);

$result = file_get_contents('http://example.com/send.php', false, $context);

我收到服务器错误.

推荐答案

content 选项用于 POST 和 PUT 请求.对于 GET，您可以将其附加为查询字符串:

The content option is used with POST and PUT requests. For GET you can just append it as a query string:

file_get_contents('http://example.com/send.php?'.$getdata, false, $context);

此外，method 默认为 GET，因此您甚至不需要设置选项，也不需要创建流上下文.因此，对于这种特殊情况，您可以根据需要简单地使用第一个参数调用 file_get_contents.

Furthermore, the method defaults to GET so you don't even need to set options, nor create a stream context. So, for this particular situation, you could simply call file_get_contents with the first parameter if you wish.

相关文章