gridview中的Yii2自定义sql查询
我对 Yii2 很陌生.我正在使用高级结构
I'm quite new to Yii2. I'm using advanced structure
我需要在不使用模型的情况下在视图中显示自定义 sql 结果,因为我想显示一个 sql 视图.
I need to show a custom sql result in a view without using a model because I would like to display a sql view.
index.php
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
['class' => 'yiigridSerialColumn'],
'COD_RISORSA',
[
'label' =>"Nome",
'attribute' => 'NOME',
'value'=>function($data){
return $data["NOME"];
}
],
'COGNOME',
['class' => 'yiigridActionColumn'],
],
]); ?>
VRisorseController.php
VRisorseController.php
public function actionIndex()
{
$totalCount = Yii::$app->db->createCommand('SELECT COUNT(*) FROM v_risorse')->queryScalar();
$dataProvider = new SqlDataProvider([
'sql' => 'SELECT * FROM v_risorse',
'totalCount' => $totalCount,
'sort' =>false,
'pagination' => [
'pageSize' => 10,
],
]);
return $this->render('index', [
'dataProvider' => $dataProvider,
]);
}
在以下网址:http://localhost/advanced/frontend/web/index.php?r=vrisorse%2Findex
我有错误:
不支持 – yiiaseNotSupportedException 消息格式 'number'仅支持整数值.你必须安装 PHP intl扩展以使用此功能.1.在C:xampphtdocsadvancedvendoryiisoftyii2i18nMessageFormatter.php
Not Supported – yiiaseNotSupportedException Message format 'number' is only supported for integer values. You have to install PHP intl extension to use this feature. 1. in C:xampphtdocsadvancedvendoryiisoftyii2i18nMessageFormatter.php
我尝试注释gridview中的所有列,错误似乎与$dataProvider
变量有关
I tried to comment all the columns in gridview, and the error seems to be related to $dataProvider
variable
'COD_RISORSA','NOME', 'COGNOME'
是选择的列.
推荐答案
您需要安装 PHP intl 扩展.我有同样的错误
You need to install PHP intl extension.i had the same error
下面给出的是我的工作代码在控制器中
given below is my working code in controller
$count = Yii::$app->db->createCommand('
SELECT COUNT(*) FROM screen_ticket_booking_history WHERE status=:status
', [':status' => 0])->queryScalar();
$sql = "SELECT A1.booking_id As Booking_id,
A1.booking_date As Booking_date,
A2.movie_name As Movie,
A3.theatre_name As Theatre,
A1.amount As Amount
FROM
screen_ticket_booking_history A1
LEFT OUTER JOIN movies A2 ON A1.movie_id=A2.id
LEFT OUTER JOIN theatres A3 ON A1.theatre_id=A3.id
LEFT OUTER JOIN users_backend A4 ON A3.users_backend_id=A4.id
WHERE A1.booking_date = '{$day}'
AND A1.movie_id='{$movies->id}'";
//~ $models = $dataProvider->getModels(); //print_r($models);die();
if( $userid != '1')
{
$sql .= " AND A3.users_backend_id = '{$userid}' ";
}
$dataProvider = new SqlDataProvider([
'sql' => $sql,
'totalCount' => $count,
]);
return $this->render('index',
[ 'model' => $model,
'dataProvider' => $dataProvider,
]);
}
以下是我的观点
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
['class' => 'yiigridSerialColumn'],
'Booking_id',
'Booking_date',
'Movie',
'Theatre',
'Amount',
//~ ['class' => 'yiigridActionColumn'],
],
]); ?>
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