PHP 中的命名空间阻止使用 Yii 静态函数
我刚刚在我的小应用程序中实现了命名空间,如下所述:http://www.yiiframework.com/doc/guide/1.1/en/basics.namespace
I just implemented namespaces in my small application as outlined here: http://www.yiiframework.com/doc/guide/1.1/en/basics.namespace
我遇到了一个问题,我的控制器将不再访问 Yii::app()->getRequest();
说它找不到 include(C:UserskuhlhtdocsinstaLabelapplicationprotectedcomponentsYii.php):无法打开流:没有那个文件或目录
.
I'm running into an issue where my controller will no longer access Yii::app()->getRequest();
saying it can't find include(C:UserskuhlhtdocsinstaLabelapplicationprotectedcomponentsYii.php): failed to open stream: No such file or directory
.
我意识到这是因为我将命名空间声明为应用程序/组件.但我不知道如何解决这个问题...
I realize that's because I declared the namespace as application/components. But I'm not sure how to work around this one...
<?php
namespace applicationcomponents;
/**
* Controller is the customized base controller class.
* All controller classes for this application should extend from this base class.
*/
class Controller extends CController {
/* @var $request CHttpRequest */
protected $request = null;
/**
* @var string the default layout for the controller view. Defaults to '//layouts/column1',
* meaning using a single column layout. See 'protected/views/layouts/column1.php'.
*/
public $layout='//layouts/column1';
/**
* @var array context menu items. This property will be assigned to {@link CMenu::items}.
*/
public $menu=array();
/**
* @var array the breadcrumbs of the current page. The value of this property will
* be assigned to {@link CBreadcrumbs::links}. Please refer to {@link CBreadcrumbs::links}
* for more details on how to specify this property.
*/
public $breadcrumbs=array();
public function __construct ($id, $module = null) {
parent::__construct($id, $module);
$this->request = Yii::app()->getRequest();
}
推荐答案
你需要完全限定相对类名Yii
.
You need to fully qualify the relative class name Yii
.
最方便的方法是导入类:只需在命名空间声明下方添加 use Yii;
.
The most convenient way to do this is by importing the class: just add use Yii;
below your namespace declaration.
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