cron 如何根据日期输出到新的日志文件?
我想将 cron 输出记录到一个过时的文件中 — /tmp/log/cron-2014-12-17.log
I'd like to log cron output to a dated file — /tmp/log/cron-2014-12-17.log
$ mkdir /tmp/log
$ chmod 777 /tmp/log
$ ls -lah /tmp/log
drwxrwxrwx 2 root root 4.0K Dec 17 21:51 .
Cron(通过root 用户)
Cron (via root user)
* * * * * /usr/bin/php /path/to/script.php > /tmp/log/cron-$(date "+%F").log 2>&1
/tmp/log 每分钟后保持为空.
如果我从命令行手动运行脚本，则会创建一个日志文件，并且输出符合预期.
If I run the script manually from command line a log file is created, and output is as expected.
// Running it manually as a CLI works fine, but not as a cron
$ /usr/bin/php /path/to/script.php > /tmp/log/cron-$(date "+%F").log 2>&1
此外，如果我创建一个文件并 chmod 777 它，cron 将 将输出写入这个创建的文件.它只是不会即时创建一个.
Also, if I create a file and chmod 777 it, the cron will write output to this created file. It just won't create one on the fly.
// Let's create it first
$ touch /tmp/log/cron.log
$ chmod 777 /tmp/log/cron.log
// wait for the next minute...
$ tail -f /tmp/log/cron.log
output... output... output...
但这不适用于 /tmp/log/cron-2014-12-17.log 之类的动态名称.
But this doesn't work for dynamic names like /tmp/log/cron-2014-12-17.log.
我错过了什么?
推荐答案
这将解决您的问题:
0 0 * * * /some/path/to/a/file.php >> /tmp/log/cron-`date +\%F`.log 2>&1
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