将 $_GET 参数传递给 cron 作业
我是 cron 工作的新手，不确定这是否可行.
I am new at cron jobs and am not sure whether this would would work.
出于安全目的，我考虑制作一个单页脚本来查找某些 GET 值(用户名、密码和安全代码)，以确保只有计算机和了解所有 3 个值的人才能运行该命令.
For security purposes I thought about making a one page script that looks for certain GET values (a username, a password, and a security code) to make sure that only the computer and someone that knows all 3 can run the command.
我制作了脚本并且它可以在浏览器中运行它，但是是否可以使用 GET 值运行 cron 作业?
I made the script and it works running it in a browser but is it possible to run the cron job with GET values?
一个例子是我跑步
* 3 * * * /path_to_script/cronjob.php?username=test&password=test&code=1234
这可能吗?
推荐答案
$_GET[] &$_POST[] 关联数组仅在您的脚本通过 Web 服务器调用时初始化.当通过命令行调用时，参数在 $argv 中传递 数组，就像 C 一样.
The $_GET[] & $_POST[] associative arrays are only initialized when your script is invoked via a web server. When invoked via the command line, parameters are passed in the $argv array, just like C.
包含传递给脚本的所有参数的数组，当从命令行运行.
Contains an array of all the arguments passed to the script when running from the command line.
你的命令是:
* 3 * * * /path_to_script/cronjob.php username=test password=test code=1234
然后您将使用 parse_str() 来设置和访问参数:
You would then use parse_str() to set and access the paramaters:
<?php
var_dump($argv);
/*
array(4) {
[0]=>
string(27) "/path_to_script/cronjob.php"
[1]=>
string(13) "username=test"
[2]=>
string(13) "password=test"
[3]=>
string(9) "code=1234"
}
*/
parse_str($argv[3], $params);
echo $params['code']; // 1234
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