使用php扫描目录和子目录中的文件并将其路径存储在数组中

2022-01-01 00:00:00 directory php

我不想扫描目录及其子目录中的所有文件.并在数组中获取它们的路径.就像数组中目录中文件的路径将只是

I want not scan all the files in a directory and its sub-directory. And get their path in an array. Like path to the file in the directory in array will be just

路径 -> text.txt

path -> text.txt

而子目录中文件的路径为

while the path to a file in sub-directory will be

somedirectory/text.txt

somedirectory/text.txt

我可以扫描单个目录，但它返回所有文件和子目录，无法区分.

I am able to scan single directory, but it returns all the files and sub-directories without any ways to differentiate. 

    if ($handle = opendir('fonts/')) {
    /* This is the correct way to loop over the directory. */
    while (false !== ($entry = readdir($handle))) {
        echo "$entry<br/>";
    }


    closedir($handle);
    }

获取目录和子目录中所有文件及其路径的最佳方法是什么?

What is the best way to get all the files in the directory and sub-directory with its path?

推荐答案

使用 SPL 中的 DirectoryIterator 可能是最好的方法:

Using the DirectoryIterator from SPL is probably the best way to do it:

$it = new RecursiveIteratorIterator(new RecursiveDirectoryIterator('.'));
foreach ($it as $file) echo $file."
";

$file 是一个 SPLFileInfo-object.它的 __toString() 方法将为您提供文件名，但还有其他几种方法也很有用！

$file is an SPLFileInfo-object. Its __toString() method will give you the filename, but there are several other methods that are useful as well!

更多信息参见:http://www.php.net/manual/en/class.recursivedirectoryiterator.php

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