php计算爆炸后的字符串数

2021-12-30 00:00:00 arrays count php explode

这是我的代码

<?php

$string = 'a|b|c|d|e|f';

$tags = explode('|' , $string);


foreach($tags as $i =>$key) {
$i >0;
    echo $i.' '.$key .'</br>';

}

?>

输出是

0 a
1 b
2 c
3 d
4 e
5 f

爆炸后我正在尝试计算字符串的数量|(在我的例子中应该是 6)我还需要我的 $i 从 1 开始而不是 0

What i'm try to count the number of strings after i exploded | (it should be 6 for my example) also i need my $i to start from 1 not 0

有什么想法吗?

谢谢.

推荐答案

<?php

$string = 'a|b|c|d|e|f';

$tags = explode('|' , $string);


foreach($tags as $i =>$key) {

    echo $i.' '.$key .'</br>';

}

?>

尝试使用:

echo count($tags); // Output of 6

数组以 0 的键开始,而不是 1.因此,当使用除计数之外的任何其他内容时,您将不断得到比预期少 1(除非您在计数之前修改数组)

Arrays start with a key of 0, not one. So when using anything else apart from count, you will constantly get 1 less than your expected (unless you modify the array prior to counting)

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