如何通过网页将参数传递给 PHP 脚本?
每当网页加载时，我都会调用 PHP 脚本.但是，PHP 脚本需要运行一个参数(我通常在测试脚本时通过命令行传递).
I am calling a PHP script whenever a webpage loads. However, there is a parameter that the PHP script needs to run (which I normally pass through the command line when I am testing the script).
如何在每次加载页面时运行脚本时传递此参数?
How can I pass this argument every time the script is run when the page loads?
推荐答案
大概你在命令行中传递参数如下:
Presumably you're passing the arguments in on the command line as follows:
php /path/to/wwwpublic/path/to/script.php arg1 arg2
... 然后在脚本中这样访问它们:
... and then accessing them in the script thusly:
<?php
// $argv[0] is '/path/to/wwwpublic/path/to/script.php'
$argument1 = $argv[1];
$argument2 = $argv[2];
?>
通过 HTTP 传递参数(通过网络访问脚本)时您需要做的是使用查询字符串并通过 $_GET 超全局变量访问它们:
What you need to be doing when passing arguments through HTTP (accessing the script over the web) is using the query string and access them through the $_GET superglobal:
转到 http://yourdomain.com/path/to/script.php?argument1=arg1&argument2=arg2
...和访问:
<?php
$argument1 = $_GET['argument1'];
$argument2 = $_GET['argument2'];
?>
如果你想让脚本运行，而不管你从哪里调用它(命令行或浏览器)，你需要像下面这样:
If you want the script to run regardless of where you call it from (command line or from the browser) you'll want something like the following:
正如 Cthulhu 在评论中指出的那样，测试您正在执行的环境的最直接方法是使用 PHP_SAPI 常量.我已经相应地更新了代码:
as pointed out by Cthulhu in the comments, the most direct way to test which environment you're executing in is to use the PHP_SAPI constant. I've updated the code accordingly:
<?php
if (PHP_SAPI === 'cli') {
$argument1 = $argv[1];
$argument2 = $argv[2];
}
else {
$argument1 = $_GET['argument1'];
$argument2 = $_GET['argument2'];
}
?>
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