使用 PDO 回显显示表中的所有行
我正在尝试使用 PDO 回显表的所有行,但遇到了问题.
I'm trying to echo out all the rows of a table using PDO but am running into trouble.
用旧的方式做我会这样做
With the old way of doing I'd have done it like
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result)){
$title= $row['title'];
$body= $row['body'];
}
但是我正在尝试使用 PDO;
But with PDO I'm trying;
$result = $db->prepare("SELECT title, body FROM post");
$result->execute();
while ($row = $db->fetchAll(PDO::FETCH_ASSOC))
{
$title = $row['title'];
$body = $row['body'];
}
echo $title;
echo $body;
它一直给我调用未定义的方法 PDO::fetchAll()
Which keeps giving me Call to undefined method PDO::fetchAll()
做手册中给出的例子
<?php
$sth = $dbh->prepare("SELECT name, colour FROM fruit");
$sth->execute();
/* Fetch all of the remaining rows in the result set */
print("Fetch all of the remaining rows in the result set:
");
$result = $sth->fetchAll();
print_r($result);
?>
有效,但我认为我无法像使用 $row=['blah']; 那样控制各个列.我呢?它也像这样打印出来;比较丑:
Works, but I don't think I have control over the individual colums like I would with a $row=['blah']; do I? It also prints out like this; rather ugly:
Array ( [0] => Array ( [title] => 这是数据库中输入的测试标题[0]
Array ( [0] => Array ( [title] => This is the test title entered in the database[0]
需要做什么才能正确使用 PDO 来做到这一点?
What needs to be done to properly use PDO to do this?
推荐答案
change:
while ($row = $db->fetchAll(PDO::FETCH_ASSOC))
{
$title = $row['title'];
$body = $row['body'];
}
到:
while ($row = $result->fetch(PDO::FETCH_ASSOC))
{
$title = $row['title'];
$body = $row['body'];
}
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