迭代来自 preg_match_all 的匹配项
我想弄清楚这个插件在 WordPress 中的机制.我有一个看起来像这样的 preg_match_all 函数:
I am trying to figure out the mechanics of this plugin in WordPress. I have a preg_match_all function that looks like this:
preg_match_all('/(?<=\[\[).+?(?=\]\])/', $content, $matches, PREG_PATTERN_ORDER);
$numMatches = count($matches[0]);
for ($i = 0; $i < $numMatches; $i++) {
$postSlug = $matches[0][$i];
}
如果我理解正确，count($matches[0]) 假设 $content 中只有一个匹配项.
If I understand this correctly, count($matches[0]) assumes there is only one match in $content.
我的目标是重新编写 for 语句以允许 preg_match_all 脚本中的完整匹配数组.
My goal here is to re-write the for statement to allow for the full array of matches in the preg_match_all script.
我假设我应该用 foreach ($matches as $postSlug) 替换 for 语句，甚至不打扰令人困惑的 $matches[0][$i]代码>在最后.
I'm assuming I should replace the for statement with foreach ($matches as $postSlug) and not even bother with the confusing $matches[0][$i] at the end.
不幸的是，最终输出似乎没有遍历数组中的每个元素.有任何想法吗?谢谢！
Unfortunately the final output does not seem to loop through each element in the array. Any ideas? Thanks!
推荐答案
如果我理解正确，count($matches[0] 假设 $content 中只有一个匹配项.
If I understand this correctly, count($matches[0] assumes there is only one match in $content.
不完全是；$matches[0] 表示整个正则表达式中的匹配数组(而不是 $matches[1]，它是匹配数组在正则表达式的第一个匹配组中).因此，count($matches[0]) 是第一个匹配组中的匹配数.
Not quite; $matches[0] represents the array of matches in of the whole regular expression (as opposed to, say, $matches[1], which would be the array of matches in the first match group of the regular expression). Thus, count($matches[0]) is the number of matches in he first match group.
你可以按照你说的做，将 for 循环重写为 foreach 循环，但这可能不会改变任何东西，因为这两种方法都应该遍历所有$matches[0] 中的元素.您确定您要查找的结果与您的正则表达式匹配吗?
You could do what you've said and rewrite the for loop as a foreach loop, but this likely won't change anything, as both methods should traverse all elements in $matches[0]. Are you certain that the results you're looking for are matched in your regular expression?
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