通过php将html表单数据发送到sql数据库(使用mysqli)
我想将输入到 html 表单中的数据发送到我的 sql 数据库，即创建一个新行，将某些值归因于某些列.我知道有类似的问题，我阅读了答案，但似乎没有任何效果.
I want to send the data inputted into an html form to my sql database, i.e., create a new row attributing certain values to certain columns. I know there are similar questions, I read the answers but nothing seems to work.
send_post.php
send_post.php
<?php
//Connecting to sql db.
$connect = mysqli_connect("my host","my user","my passwrod","my db");
//Sending form data to sql db.
mysqli_query($connect,"INSERT INTO posts (category, title, contents, tags)
VALUES ('$_POST[post_category]', '$_POST[post_title]', '$_POST[post_contents]', '$_POST[post_tags]')";
?>
post.html#form
post.html#form
<form onSubmit="send_post.php" method="post">
<h3>Category:</h3>
<input type="text" name="post_category">
<h3>Post title:</h3>
<input type="text" name="post_title">
<h3>Post tags (a,b,c...):</h3>
<input type="text" name="post_tags">
<h3>Post (use html):</h3>
<textarea rows="20" cols="50" name="post_contents"></textarea>
<input type="submit">
</form>
我的数据库posts"表列:
my db "posts" table colums:
pid
title
contents
tags
category
pid 开启了 auto_increment
我已经尝试以正确"的顺序向所有列发送值，包括 pid.
I have already tried sending values to all colunes, including pid, and in the "right" order.
mysqli_connect 部分不是问题，因为我从我的一个不同的 .php 文件中复制了它.
The mysqli_connect part isn't the issue since I copied it from a different .php file of mine that works.
服务器 php-sql 兼容性也不是问题，因为我成功地有一个不同的 .php 文件从数据库中检索数据(手动插入的数据).
Server php-sql compatibility isn't the issue either, since I successfully had a different .php file retrieve data from the db (data which was manually inserted).
推荐答案
改变这个
<form onSubmit="send_post.php" method="post">
到
<form action="send_post.php" method="post">
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