MYSQLi bind_result 返回 null
我试图在查询中输出从数据库中获取的变量,但没有返回任何内容.使用 MYSQLi 准备好的语句.
I am trying to output the variables that I get from the database in my query but nothing is being returned. Using MYSQLi prepared statements.
请看下面的代码:
$stmt = $con->prepare("SELECT first_name, last_name FROM transactions WHERE order_id = ?");
$stmt->bind_param('i', $order_id);
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($first_name, $last_name);
$stmt->close();
// Output review live to page
echo $first_name;
我哪里出错了?
推荐答案
您忘记了获取结果的行.fetch()
.
You forgot the line to fetch the result. fetch()
.
试试:
$stmt->bind_result($first_name, $last_name);
$stmt->fetch(); // ----- > you forget that line to fetch results.
$stmt->close();
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