php 5.2.6 的 mysqli_stmt_get_result 替代方案

Specifically, in this case, how can I solve the mysqli_stmt_get_result undefined function available on > 5.3 ? Here is the code:

  $stmt = mysqli_prepare($con,$db_query);

  if($stmt) {

     mysqli_stmt_bind_param($stmt,'ss',$after,$lang);
     mysqli_stmt_execute($stmt);
     $result = mysqli_stmt_get_result($stmt); // <-- getting undefined error here !!!

     $updated = array();
     $deleted = array();

     while($row = mysqli_fetch_assoc($result)) {

        if($row['status']==1) {
           array_push($updated,$row);
        } else {
           $cardName=$row['cardName'];
           $cardStatus=$row['status'];
           $cardId=$row['cardId'];
           $language=$row['language'];
           array_push($deleted,array(
                    'cardName'=>$cardName,
                                    'status'=>$cardStatus,
                                    'cardId'=>$cardId,
                                    'language'=>$language
                               )
           );
        }
     }

     $response = array(
        'cards'=>array(
           'updated'=>$updated,
           'deleted'=>$deleted
        )
     );

     $json = json_encode($response);
     mysqli_close($con);
     echo $json;

  }

关键是我使用的是准备好的语句，由于我缺乏 php 知识，我发现没有其他方法可以在不重写整个脚本的情况下解决问题.