使用 MySQLi 和 PHP 的 HTML 表
我正在尝试制作一个连接到我的数据库的表,以便我可以使用该数据库中的信息.
I'm trying to make a table connected to my database so I can use the information in that database.
我认为我的方法是正确的,但目前表格只显示第一行.任何人对发生的事情有任何想法吗?
I think I'm on the right way, but currently the table only displays the first row. Anyone got any ideas on what's going on?
<table id="fairtable">
<tr>
<td>Fair Name</td>
<td>Date</td>
<td>Are we there?</td>
<td>Website</td>
</tr>
<?php
$sql = "SELECT `name`,`date`,`present`,`website` FROM `dates`";
$results = mysqli_query($conn,$sql);
while($rowitem = mysqli_fetch_array($results)) {
echo "<tr>";
echo "<td>" . $rowitem['name'] . "</td>";
echo "<td>" . $rowitem['date'] . "</td>";
echo "<td>" . $rowitem['present'] . "</td>";
echo "<td>" . $rowitem['website'] . "</td>";
echo "</tr>";
}
?>
</table>
推荐答案
这可能是因为您没有正确打开 HTML 表格标签,这很容易被忽略.还在白色语句中循环结果集:
Perhaps this is because you have not opened your HTML table tags correctly, its an easy thing to overlook. Also loop the result set inside a white statement:
$sql = "SELECT `name`,`date`,`present`,`website` FROM `dates`";
$results = mysqli_query($conn,$sql);
echo "<table>"; //begin table tag...
//you can add thead tag here if you want your table to have column headers
while($rowitem = mysqli_fetch_array($results)) {
echo "<tr>";
echo "<td>" . $rowitem['name'] . "</td>";
echo "<td>" . $rowitem['date'] . "</td>";
echo "<td>" . $rowitem['present'] . "</td>";
echo "<td>" . $rowitem['website'] . "</td>";*/
echo "</tr>";
}
echo "</table>"; //end table tag
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