php preg_replace regex 替换两个字符串之间的字符串
我有以下问题:我想替换(在 php 中)一个特殊字符，但前提是它位于其他两个字符之间.它试图用 preg_replace 找到解决方案，但没有奏效.
I have the following problem: I want to replace (in php) a special character, but only if it's between two other characters. It tried to find a solution with with preg_replace but it doesn't work.
我想替换每一个；带有 : 介于 "示例:
I want to replace every ; with a : which is between the " The Examples:
$orig_string= 'asbas;"asd;";asd;asdadasd;"asd;adsas"'
结果应该是:
'asbas;"asd:";asd;asdadasd;"asd:adsas"'
我尝试了几个正则表达式，但没有任何成功......
I tried several regexes but without any succes...
我试过的两个例子:
$result = preg_replace('(?<=")(.*)(;)(.*)(?=")',':', $str);
$result = preg_replace('.*".*(;).*"',':', $str);
有人可以帮我吗?
非常感谢
V
推荐答案
在这里你不需要使用环顾四周.可以写成
You need not use look arounds here. It can be written as
("[^";]*);([^"]*")
替换为 1:2
正则表达式演示
测试
preg_replace ("/("[^";]*);([^"]*")/m", "\1:\2", 'asbas;"asd;";asd;asdadasd;"asd;adsas"' );
=> asbas;"asd:";asd;asdadasd;"asd:adsas"
更新:
;(?!(?:"[^"]*"|[^"])*$)
只需将匹配的 ; 替换为 :
Just replace the matched ; with :
演示
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