PHP:如何检查日期是今天、昨天还是明天
我想检查一下日期是今天、明天、昨天还是其他日期.但是我的代码不起作用.
I would like to check, if a date is today, tomorrow, yesterday or else. But my code doesn't work.
代码:
$timestamp = "2014.09.02T13:34";
$date = date("d.m.Y H:i");
$match_date = date('d.m.Y H:i', strtotime($timestamp));
if($date == $match_date) {
//Today
} elseif(strtotime("-1 day", $date) == $match_date) {
//Yesterday
} elseif(strtotime("+1 day", $date) == $match_date) {
//Tomorrow
} else {
//Sometime
}
代码总是在 else 情况下.
The Code always goes in the else case.
推荐答案
第一. 你在使用函数 strtotime 时出错了，见 PHP 文档
First. You have mistake in using function strtotime see PHP documentation
int strtotime ( string $time [, int $now = time() ] )
您需要修改代码以将整数时间戳传递给此函数.
You need modify your code to pass integer timestamp into this function.
第二.您使用包含时间部分的格式 d.m.Y H:i.如果您只想比较日期，则必须删除时间部分，例如`$date = date("d.m.Y");``
Second. You use format d.m.Y H:i that includes time part. If you wish to compare only dates, you must remove time part, e.g. `$date = date("d.m.Y");``
第三.我不确定它是否对您的工作方式相同，但我的 PHP 无法理解 $timestamp 中的日期格式并返回 01.01.1970 02:00 进入 $match_date
Third. I am not sure if it works in the same way for you, but my PHP doesn't understand date format from $timestamp and returns 01.01.1970 02:00 into $match_date
$timestamp = "2014.09.02T13:34";
date('d.m.Y H:i', strtotime($timestamp)) === "01.01.1970 02:00";
您需要检查 strtotime($timestamp) 是否返回正确的日期字符串.如果没有，您需要指定在 $timestamp 变量中使用的格式.您可以使用以下功能之一来执行此操作 date_parse_from_format 或 DateTime::createFromFormat
You need to check if strtotime($timestamp) returns correct date string. If no, you need to specify format which is used in $timestamp variable. You can do this using one of functions date_parse_from_format or DateTime::createFromFormat
这是一个工作示例:
$timestamp = "2014.09.02T13:34";
$today = new DateTime("today"); // This object represents current date/time with time set to midnight
$match_date = DateTime::createFromFormat( "Y.m.d\TH:i", $timestamp );
$match_date->setTime( 0, 0, 0 ); // set time part to midnight, in order to prevent partial comparison
$diff = $today->diff( $match_date );
$diffDays = (integer)$diff->format( "%R%a" ); // Extract days count in interval
switch( $diffDays ) {
case 0:
echo "//Today";
break;
case -1:
echo "//Yesterday";
break;
case +1:
echo "//Tomorrow";
break;
default:
echo "//Sometime";
}
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