检查方法是否存在于同一个类中
因此,method_exists()
需要一个对象来查看方法是否存在.但是我想知道同一个类中是否存在一个方法.
So, method_exists()
requires an object to see if a method exists. But I want to know if a method exists from within the same class.
我有一个方法可以处理一些信息并可以接收一个动作,它运行一个方法来进一步处理该信息.我想在调用之前检查该方法是否存在.我怎样才能实现它?
I have a method that process some info and can receive an action, that runs a method to further process that info. I want to check if the method exists before calling it. How can I achieve it?
示例:
class Foo{
public function bar($info, $action = null){
//Process Info
$this->$action();
}
}
推荐答案
你可以这样做:
class A{
public function foo(){
echo "foo";
}
public function bar(){
if(method_exists($this, 'foo')){
echo "method exists";
}else{
echo "method does not exist";
}
}
}
$obj = new A;
$obj->bar();
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