Laravel 5.3 - htmlspecialchars() 期望参数 1 为字符串
我是 Laravel 的新手,我很喜欢它.在处理社交媒体项目时,我收到此错误:htmlspecialchars() 期望参数 1 为字符串,给定对象(视图:C:wamp64wwwhistoirevraieesourcesviewsuserprofile.blade.php)
I am new to laravel and I am enjoying it. While working on a social media project I got this error: htmlspecialchars() expects parameter 1 to be string, object given (View: C:wamp64wwwhistoirevraieesourcesviewsuserprofile.blade.php)
我在这个网站上检查了一些问题,但我没有找到解决我问题的问题.
I have checked some questions on this site but I have not found a question that solves my problem.
这是我的 profile.blade.php
的组成:
<ul class="profile-rows">
<li>
<span class="the-label">Last visit: </span>
<span class="the-value mark green">{{ CarbonCarbon::createFromFormat('Y-m-d H:i:s', $user->lastVisit)->diffForHumans(CarbonCarbon::now())}}</span>
</li>
<li>
<span class="the-label">Member since: </span>
<span class="the-value mark light-gray">{{ $user->created_at->format('F Y') }}</span>
</li>
<li>
<span class="the-label">Profile views: </span>
<span class="the-value mark light-gray">5146</span>
</li>
<li>
<span class="the-label">Living In: </span>
<span class="the-value">{{ $user->town }}</span>
</li>
<li>
<span class="the-label">Website: </span>
<span class="the-value"><a href="{{ url($user->website) }}">{{ $user->website }}</a></span>
</li>
</ul>
有关用户的所有信息均由控制器提供:
All the information about the user are given by a controller:
public function index($username){
$user = User::where('username', $username)->first();
return view('user.profile', compact('user'));
}
请帮我解决这个问题!
推荐答案
我认为你的 $user->website
是空的/空白的.
I think your $user->website
is empty/blank.
如果您查看 url()
辅助方法,如果 $path
为空,Laravel 将返回 UrlGenerator
的实例.
If you look at the url()
helper method, Laravel will return an instance of UrlGenerator
if $path
is null.
所以在你的情况下,如果 $user->website
是空的,你会得到 UrlGenerator
回来,因此你关于 htmlspecialchars
的错误得到一个对象.
So in your case if $user->website
is empty, you'd get UrlGenerator
back and thus your error about htmlspecialchars
getting an object.
一个简单的解决方案是用检查包裹你的 html 块:
One simple solution would be to wrap your html chunk with a check:
@if($user->website)
<li>
...
</li>
@endif
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