如何在Android中获取两个时间的分钟差
public int difftime(String string, String string2) {
int hours;
int min = 0;
int days;
long difference ;
try {
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("HH:mm");
Date date1 = simpleDateFormat.parse("08:00 AM");
Date date2 = simpleDateFormat.parse("04:00 PM");
difference = date2.getTime() - date1.getTime();
days = (int) (difference / (1000 * 60 * 60 * 24));
hours = (int) ((difference - (1000 * 60 * 60 * 24 * days)) / (1000 * 60 * 60));
min = (int) (difference - (1000 * 60 * 60 * 24 * days) - (1000 * 60 * 60 * hours))
/ (1000 * 60);
hours = (hours < 0 ? -hours : hours);
Log.i("======= Hours", " :: " + hours);
return min;
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return min;
}
这是我的函数,以分钟为单位获取时间差,但它始终为零。我不知道我哪里搞错了,请告诉我哪里搞错了。我希望会议记录形式的结果。
解决方案
首先,您犯了非常基本的错误。对于12小时制,您应该使用HH而不是HH。令我惊讶的是,没有一个答案能纠正这个错误。
其次,您考虑的不是日期,而是时间。所以上午8:00和下午4:00没有任何分钟差异。只有8小时的差异。
因此,现在在您的情况下,您必须根据两种情况计算分钟,一种是从小时计算,另一种是当存在分钟差时计算分钟。我改正你的代码。请检查一下,因为这在我这一端工作正常。public long diffTime() {
long min = 0;
long difference ;
try {
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("hh:mm aa"); // for 12-hour system, hh should be used instead of HH
// There is no minute different between the two, only 8 hours difference. We are not considering Date, So minute will always remain 0
Date date1 = simpleDateFormat.parse("08:00 AM");
Date date2 = simpleDateFormat.parse("04:00 PM");
difference = (date2.getTime() - date1.getTime()) / 1000;
long hours = difference % (24 * 3600) / 3600; // Calculating Hours
long minute = difference % 3600 / 60; // Calculating minutes if there is any minutes difference
min = minute + (hours * 60); // This will be our final minutes. Multiplying by 60 as 1 hour contains 60 mins
} catch (Throwable e) {
e.printStackTrace();
}
return min;
}
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