SimpleDateFormat getHors()返回不正确的值
为什么"09:50"的getHour()返回8? 代码:
SimpleDateFormat sdf = new SimpleDateFormat("HH:mm");
Date date = sdf.parse("09:50");
int hours = date.getHours(); // return 8 instead of 9 ???
解决方案
您的SimpleDateFormat可能尚未设置为默认时区。 呼叫:
sdf.setTimeZone(TimeZone.getDefault());
在解析文字之前,应该可以解决您的问题。 我测试了以下代码:
...
public static final SimpleDateFormat CDfTimestamp = new SimpleDateFormat(
"yyyy-MM-dd HH:mm:ss");
...
Date da1 = null;
for (String dl1 : new String[] { "1970-01-01 12:34:56",
"2016-01-01 12:34:56" }) {
try {
CDfTimestamp.setTimeZone(TimeZone.getTimeZone("GMT+05:00"));
da1 = CDfTimestamp.parse(dl1);
System.out.printf("parse GMT+05:00 %s -> %d %d %d (os=%d)
", dl1, da1
.getHours(), da1.getMinutes(), da1.getSeconds(), CDfTimestamp
.getTimeZone().getOffset(0));
CDfTimestamp.setTimeZone(TimeZone.getTimeZone("UTC"));
da1 = CDfTimestamp.parse(dl1);
System.out.printf("parse UTC %s -> %d %d %d (os=%d)
", dl1, da1
.getHours(), da1.getMinutes(), da1.getSeconds(), CDfTimestamp
.getTimeZone().getOffset(0));
CDfTimestamp.setTimeZone(TimeZone.getDefault());
da1 = CDfTimestamp.parse(dl1);
System.out.printf("parse default %s -> %d %d %d (os=%d)
", dl1, da1
.getHours(), da1.getMinutes(), da1.getSeconds(), CDfTimestamp
.getTimeZone().getOffset(0));
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
...
获取以下输出:
parse GMT+05:00 1970-01-01 12:34:56 -> 8 34 56 (os=18000000)
parse UTC 1970-01-01 12:34:56 -> 13 34 56 (os=0)
parse default 1970-01-01 12:34:56 -> 12 34 56 (os=3600000)
parse GMT+05:00 2016-01-01 12:34:56 -> 8 34 56 (os=18000000)
parse UTC 2016-01-01 12:34:56 -> 13 34 56 (os=0)
parse default 2016-01-01 12:34:56 -> 12 34 56 (os=3600000)
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