Java和Espresso-can-t输入,需要支持输入法,或者可以从类:Class SearchView赋值
我正在尝试使用Espresso来测试具有此XML的应用程序:
<com.google.android.material.textfield.TextInputLayout
android:id="@+id/tvLogin"
android:layout_width="0dp"
android:layout_height="wrap_content"
android:hint="myHint"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent">
<com.google.android.material.textfield.TextInputEditText
android:layout_width="match_parent"
android:layout_height="56dp"
android:imeOptions="flagNoExtractUi|actionNext"
android:inputType="text" />
</com.google.android.material.textfield.TextInputLayout>
这是我尝试运行的测试:
onView(withId(R.id.tvLogin)).check(ViewAssertions.matches(ViewMatchers.isDisplayed()));
onView(withId(R.id.tvLogin)).perform(typeText("test"));
我收到此错误:
Caused by: java.lang.RuntimeException: Action will not be performed because the target view does not match one or more of the following constraints:
((is displayed on the screen to the user) and (supports input methods or is assignable from class: class android.widget.SearchView))
Target view: "TextInputLayout{id=2131362315, res-name=tvLogin, visibility=VISIBLE, width=831, height=144, has-focus=false, has-focusable=true, has-window-focus=true, is-clickable=false, is-enabled=true, is-focused=false, is-focusable=false, is-layout-requested=false, is-selected=false, layout-params=androidx.constraintlayout.widget.ConstraintLayout$LayoutParams@8241b55, tag=null, root-is-layout-requested=false, has-input-connection=false, x=39.0, y=39.0, child-count=2}"
解决方案
您的tvLogin
是TextInputLayout
,这也是LinearLayout
,所以当您在它上执行typeText()
时会出现错误。由于typeText()
仅适用于可编辑字段,并且TextInputEditText
是tvLogin
的后代,您可以重写测试以使用Espresso:
onView(allOf(supportsInputMethods(), isDescendantOfA(withId(R.id.tvLogin))))
.perform(typeText("test"))
或者,您也可以提供TextInputEditText
的ID:
<com.google.android.material.textfield.TextInputEditText
android:id="@+id/tvLoginEditText"
android:layout_width="match_parent"
android:layout_height="56dp"
android:imeOptions="flagNoExtractUi|actionNext"
android:inputType="text" />
,然后对可编辑字段执行typeText()
:
onView(withId(R.id.tvLoginEditText))
.perform(typeText("test"))
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