Java和Espresso-can-t输入,需要支持输入法,或者可以从类:Class SearchView赋值

2022-05-07 00:00:00 testing java android-espresso

我正在尝试使用Espresso来测试具有此XML的应用程序:

<com.google.android.material.textfield.TextInputLayout
    android:id="@+id/tvLogin"
    android:layout_width="0dp"
    android:layout_height="wrap_content"
    android:hint="myHint"
    app:layout_constraintEnd_toEndOf="parent"
    app:layout_constraintStart_toStartOf="parent"
    app:layout_constraintTop_toTopOf="parent">

    <com.google.android.material.textfield.TextInputEditText
        android:layout_width="match_parent"
        android:layout_height="56dp"
        android:imeOptions="flagNoExtractUi|actionNext"
        android:inputType="text" />

</com.google.android.material.textfield.TextInputLayout>

这是我尝试运行的测试:

onView(withId(R.id.tvLogin)).check(ViewAssertions.matches(ViewMatchers.isDisplayed()));
onView(withId(R.id.tvLogin)).perform(typeText("test"));

我收到此错误:

Caused by: java.lang.RuntimeException: Action will not be performed because the target view does not match one or more of the following constraints:
((is displayed on the screen to the user) and (supports input methods or is assignable from class: class android.widget.SearchView))
Target view: "TextInputLayout{id=2131362315, res-name=tvLogin, visibility=VISIBLE, width=831, height=144, has-focus=false, has-focusable=true, has-window-focus=true, is-clickable=false, is-enabled=true, is-focused=false, is-focusable=false, is-layout-requested=false, is-selected=false, layout-params=androidx.constraintlayout.widget.ConstraintLayout$LayoutParams@8241b55, tag=null, root-is-layout-requested=false, has-input-connection=false, x=39.0, y=39.0, child-count=2}"

解决方案

您的tvLoginTextInputLayout,这也是LinearLayout,所以当您在它上执行typeText()时会出现错误。由于typeText()仅适用于可编辑字段,并且TextInputEditTexttvLogin的后代,您可以重写测试以使用Espresso:

中的一个方便的匹配器ViewMatchers.supportInputMethods()
onView(allOf(supportsInputMethods(), isDescendantOfA(withId(R.id.tvLogin))))
    .perform(typeText("test"))

或者,您也可以提供TextInputEditText的ID:

<com.google.android.material.textfield.TextInputEditText
    android:id="@+id/tvLoginEditText"
    android:layout_width="match_parent"
    android:layout_height="56dp"
    android:imeOptions="flagNoExtractUi|actionNext"
    android:inputType="text" />

,然后对可编辑字段执行typeText()

onView(withId(R.id.tvLoginEditText))
    .perform(typeText("test"))

相关文章